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iogann1982 [59]
3 years ago
7

Katie has 36 coins in her jar (nickels, dimes, and quarters) totalling $4.20. She has twice as many dimes as quarters. How many

nickels does Katie have?
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

I think you need to mutply those. And you will get your answer.

Step-by-step explanation:

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The algebraic expression 4x2 + 3Vx+5 is a polynomial
Mila [183]

Answer:

In this problem, I can not tell what is V, so I will answer it in a general way.

A polynomial is something of the form:

a*x^5 + b*x^4 + c*x^3 + d*x^2 + e*x + f

a, b, c, d, e, and f are real numbers and constant.

Where the degree of the polynomial is equal to the greatest power (in this case 5).

You write:

4x^2 + 3Vx + 5

Now, if V is a real number, then we have that this is a polynomial of degree 2.

Because we can write this as:

4*x^2 + (3V)*x + 5

So the answer is true.

Now, if V is a variable or an operation, the answer will be false.

4 0
3 years ago
Fundamental Theorem Algebra II
Rama09 [41]
There is like no picture or description
8 0
3 years ago
1
nadya68 [22]

Answer:

64

Step-by-step explanation:

2, 6, 28, 23,7.64.

because 64 is the furthest away from any other number

5 0
2 years ago
Solve for b.
AlekseyPX

Answer:

b=+-5\sqrt{C}

Step-by-step explanation:

C=b^2/25

25C=b^2

\sqrt{b^2}=+-\sqrt{25C}

b=+-5\sqrt{C}

8 0
3 years ago
Read 2 more answers
Write a matrix equation for the given systems of equations.
REY [17]

Answer:

<em></em>\left[\begin{array}{ccc}2&-6&2\\0&3&-2\\0&2&2\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]= \left[\begin{array}{ccc}1\\-5\\-3\end{array}\right]<em></em>

Step-by-step explanation:

Given system of equations are

2x-6y-2z = 1

3y - 2z = -5

2y + 2z = -3

given

2 x - 6 y - 2 z = 1

0 x + 3 y - 2z = -5

0 x +2y + 2 z = - 3

<em>The Matrix form of the given system of equations </em>

<em>A X = B</em>

<em></em>\left[\begin{array}{ccc}2&-6&2\\0&3&-2\\0&2&2\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]= \left[\begin{array}{ccc}1\\-5\\-3\end{array}\right]<em></em>

4 0
3 years ago
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