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iogann1982 [59]

3 years ago

7

Katie has 36 coins in her jar (nickels, dimes, and quarters) totalling $4.20. She has twice as many dimes as quarters. How many

nickels does Katie have?

1 answer:

Diano4ka-milaya [45]3 years ago

4 0

Answer:

I think you need to mutply those. And you will get your answer.

Step-by-step explanation:

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Please help, and show work thank you :)

frosja888 [35]

Having a $75 added cost to the total price, we can presume they will never equal. It is easy to see if you make it algebraic:

$m=months\\t=total\\\\ProviderA => t = 39.95m\\ProviderB => t = 39.95m+75$

They will never equal each other.

3 0

3 years ago

The length of a rectangle is 3cm greater than its width. the perimeter of the rectangle is 34cm. find its length.

mamaluj [8]

Answer:

10cm

Step-by-step explanation:

The formula for perimeter is:

$P=2(l+w)$

Let the width of the rectangle be x then the length would be...

3+x

Now, let's plug these values into the equation and solve. (Note we are also given perimeter is 34 cm):

$34=2(x+3+x)\\34=2(2x+3)\\Distribute\ the\ 2\ to\ each\ term\ in\ the\ parentheses\\34=2(2x)+2(3)\\34=4x+6\\Subtract\ 6\ from\ both\ sides\\4x=28\\Divide\ both\ sides\ by\ 4\\x=7$

And since the length is x+3 then it is...

x+3=7+3=10cm

4 0

2 years ago

Read 2 more answers

HELP ME PLS n j j j hjnbhjbhbj

grin007 [14]

Answer:

C

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the simple interest rate needed in order for an investment of $2000 to grow to an account of $5000 in 3 years

Nutka1998 [239]

$\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$5000\\ P=\textit{original amount deposited}\dotfill&\$2000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &3 \end{cases} \\\\\\ 5000=2000(1+r3)\implies \cfrac{5000}{2000}=1+3r\implies \cfrac{5}{2}=1+3r \\\\\\ 5=2+6r\implies 3=6r\implies \cfrac{3}{6}=r\implies 0.5=r\implies \stackrel{\textit{converting to percent}}{0.5\cdot 100\implies 50\%}$

5 0

3 years ago

Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note

Viktor [21]

a. Recall that

$\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C$

For $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n$

By integrating both sides, we get

$\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

If $x=0$ , then

$\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0$

so that

$\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

We can shift the index to simplify the sum slightly.

$\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n$

b. The power series for $x\ln(1-x)$ can be obtained simply by multiplying both sides of the series above by $x$ .

$\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n$

c. We have

$\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)$

$\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}$

4 0

3 years ago