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2 years ago

Solve for x in the equation

Mathematics

1 answer:

Gekata [30.6K]2 years ago

8 0

Answer:

The answer for this question is c

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Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries

kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

$\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04$

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535
$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465$

64.65% probability of at least one injury commuting to work in the next 20 years

3 0

3 years ago

Which number is prime? <br> A. 21 <br> B. 23<br> C. 25<br> D. 27

IceJOKER [234]

B. 23

Hope this helps!!!!!!

5 0

3 years ago

Read 2 more answers

(HELP) A Boeing 747 airplane carries approximately 467 passengers. How many trips would it take the airplane to transport 100,00

Finger [1]

215. If you divide 100,000 by 467 you get 214.132. Since you can’t have .132 of a person you need to round up to 215

6 0

2 years ago

Read 2 more answers

How many kilometers is he from the lake when he starts riding?

Assoli18 [71]

You forgot picture.So I can't explain that

5 0

3 years ago

What are the restrictions for a? 2a^2+a-15/5a^2+16a+3

koban [17]

ANSWER

The restrictions are

$a\ne -3,a\ne -\frac{1}{5}$

EXPLANATION

We were given the rational function,

$\frac{2a^2+a-15}{5a^2+16a+3}$

The function is defined for all values of a, except

$5a^2+16a+3=0$

This has become a quadratic trinomial, so we need to split the middle term.

We do that by multiplying the coefficient of $x^2$ which is 5 by the constant term which is 3. This gives us 15.

The factors of 15 that adds up to 16 are 1 and 15.

We use these factors to split the middle term.

$5a^2+15a+a+3=0$

We now factor to get,

$5a(a+3)+1(a+3)=0$

We factor further to get,

$(a+3)(5a+1)=0$

This implies that,

$(a+3)=0,(5a+1)=0$

This gives

$a=-3,a=-\frac{1}{5}$

These are the restrictions.

8 0

3 years ago