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Daniel [21]
3 years ago
7

How do basic facts and patterns help multiply a number by a multiple of 10

Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0

when multiplying by 10 all you do is take the original number and add it 10 times.

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The explicit formula for the geometric sequence 10,30,90,180
alukav5142 [94]

Answer:

a_{n} = 10 (3)^{n-1}

Step-by-step explanation:

The n th term of a geometric sequence is

a_{n} = a (r)^{n-1}

where a is the first term and r the common ratio

Here a = 10 and r = 30 ÷ 10 = 3, thus

a_{n} = 10 (3)^{n-1}

7 0
2 years ago
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Which is the graph of y – 3 = (x + 6)?
velikii [3]

The Answer is A (The first graph in the photo), I attached the graph to help you see the answer for y-3=-\frac{2}{3}(x+6).

I hope you have a good day and please give me brainest if that is correct!

3 0
2 years ago
In circle A shown below, m is 67° and m is 74°. <br> What is m∡FDE?
deff fn [24]
Use this theorem: in a circle, the measure of an angle formed by two chords that intersect inside the circle is half the sum of the arcs formed by the chords.

In this case the sum of the arcs formed by the chords is 67° + 74° = 141 °, then the half is 141° / 2 = 70.5°.

Answer: 70.5°
8 0
3 years ago
Write an equation for when k= 1/6
Elden [556K]

Answer:

2/6 - 1/6 = k

Step-by-step explanation:

3 0
2 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
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