Ie 32^2 - 4ac=0 so ac=256 and a+c=130
So, that means:2 equations ac=256 a+c=130 ie c=130-a
So,a(130-a)=256 so 130a -a^2=256 ie a^2-130a +256=0 (a-2)(a-128)=0
Finally,giving a= 2 or a=128 so, a=2 c=128 or a=128 c=2
Since, a>c , a=128 and c=2 ie (128,2)
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)
The equation of the given line is
9x+7y=4
7y = - 9x + 4
y = -9x/7 + 4/7
Comparing with the slope intercept form, slope = - 9/7
If the line passing through the given point is perpendicular to the given line, it means its slope is the negative reciprocal of the slope of the given line.
Therefore, the slope of the line passing through (7,-4) is 7/9
To determine the intercept, we would substitute m = 7/9, x = 7 and y = -4 into y = mx + c. It becomes
- 4 = 7/9×7 + c = 49/9 + c
c = - 4 - 49/9 = -85/9
The equation becomes
y = 7x/9 - 85/9
Answer:example: -10 + -3 = -13
Step-by-step explanation:
Just add the two numbers then put the negative sign before it. (for addition only)
