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Sladkaya [172]
3 years ago
7

The quadratic equation ax^2+32x+c=0 has exactly one solution. If a+c=130, and a>c, find the ordered pair (a,c).

Mathematics
1 answer:
vitfil [10]3 years ago
4 0
Ie 32^2 - 4ac=0 so ac=256 and a+c=130 
So, that means:2 equations ac=256 a+c=130 ie c=130-a 
So,a(130-a)=256 so 130a -a^2=256 ie a^2-130a +256=0 (a-2)(a-128)=0 
Finally,giving a= 2 or a=128 so, a=2 c=128 or a=128 c=2 
Since, a>c , a=128 and c=2 ie (128,2)
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5 0
3 years ago
A car drives 16 1/2 miles on a gallon of gas. how many miles can it travel on 9 gallons?
Nana76 [90]

Answer:

148.5 miles

Step-by-step explanation:

its 148.5 miles because you times the 16 1/2 to the 9 and get 148.5 miles

5 0
3 years ago
The following set of ordered pairs is an example of direct variation, find the constant ratio between the variables. (Hint: Find
Serhud [2]
Direct variation looks like
y=kx, so

k=y/x

<span>(2, 4)      k=4/2=2
(5, 10)    k=10/5=2
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6 0
3 years ago
The price of a computer component is decreasing at a rate of 15​% per year. State whether this decrease is linear or exponential
Margaret [11]

Answer:

Since the price is given by an exponential function, the decline in price is exponential.

The component will cost $36.8475 in three years.

Step-by-step explanation:

The equation for the price of a component has the following format:

P(t) = P(0)(1-r)^{t}

In which P(t) is the price after t years, P(0) is the initial price, and r is the rate that the price decreases.

Since the price is given by an exponential function, the decline in price is exponential.

The price of a computer component is decreasing at a rate of 15​% per year.

This means that r = 0.15

Component costs ​$60 ​today

So P(0) = 60. Then

P(t) = P(0)(1-r)^{t}

P(t) = 60(1-0.15)^{t}

P(t) = 60(0.85)^{t}

What will it cost in three​ years?

This is P(3).

P(t) = 60(0.85)^{t}

P(3) = 60(0.85)^{3} = 36.8475

The component will cost $36.8475 in three years.

6 0
3 years ago
Pls some1 help I’ll help u PLSSSS HELP
kakasveta [241]

1/3 is bigger than 30%

4 0
3 years ago
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