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Sladkaya [172]
3 years ago
7

The quadratic equation ax^2+32x+c=0 has exactly one solution. If a+c=130, and a>c, find the ordered pair (a,c).

Mathematics
1 answer:
vitfil [10]3 years ago
4 0
Ie 32^2 - 4ac=0 so ac=256 and a+c=130 
So, that means:2 equations ac=256 a+c=130 ie c=130-a 
So,a(130-a)=256 so 130a -a^2=256 ie a^2-130a +256=0 (a-2)(a-128)=0 
Finally,giving a= 2 or a=128 so, a=2 c=128 or a=128 c=2 
Since, a>c , a=128 and c=2 ie (128,2)
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Answer:

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Step-by-step explanation:

Question:

Which of the following describes the correct process for solving the equation 2x − 4 = 20 and arrives at the correct solution?

a) Add 4 to both sides, and then divide by 2. The solution is x = 12.

b) Divide both sides by −4, and then subtract 2. The solution is x = −7.

c) Subtract 4 from both sides, and then divide by 2. The solution is x = −12.

d) Multiply both sides by −4, and then divide by 2. The solution is x = −40.

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2x-4=20

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