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4 years ago

The quadratic equation ax^2+32x+c=0 has exactly one solution. If a+c=130, and a>c, find the ordered pair (a,c).

1 answer:

4 0

Ie 32^2 - 4ac=0 so ac=256 and a+c=130
So, that means:2 equations ac=256 a+c=130 ie c=130-a
So,a(130-a)=256 so 130a -a^2=256 ie a^2-130a +256=0 (a-2)(a-128)=0
Finally,giving a= 2 or a=128 so, a=2 c=128 or a=128 c=2
Since, a>c , a=128 and c=2 ie (128,2)

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In this question:

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