Question

The quadratic equation ax^2+32x+c=0 has exactly one solution. If a+c=130, and a>c, find the ordered pair (a,c).

Answer 1

Ie 32^2 - 4ac=0 so ac=256 and a+c=130 
So, that means:2 equations ac=256 a+c=130 ie c=130-a 
So,a(130-a)=256 so 130a -a^2=256 ie a^2-130a +256=0 (a-2)(a-128)=0 
Finally,giving a= 2 or a=128 so, a=2 c=128 or a=128 c=2 
Since, a>c , a=128 and c=2 ie (128,2)