Problem 1
The largest value would be 1 and the smallest would be
-1.
To get a product of 1, either all are 1 or two of the
variables are -1 and the other one is 1.
Largest value = (1)^2 * (1)^3 * (1)^4 =1
Smallest value = (- 1)^2 * (- 1)^3 * (1)^4 = -1
The difference is:
largest value – smallest value = 1 – (-1) = 2
<span>Therefore the answer is letter D.</span>
Problem 2
% loss = (final price – initial price) * 100%/ initial
price
where, final price per dozen = ( $2.50 / piece) (12 piece
/ dozen) = $30
Therefore,
% loss = ($30 - $33) * 100 / $33
% loss = - 300/ 33 = 9 1/11
<span>Therefore the answer is <span>letter C.</span></span>
Answer:
84.48
Step-by-step explanation:
Formula = Number x 100
Percent = 49 x 100
58 = 84.48
The possible product can be 94.
You need the sum of two prime numbers that is divisible by seven and is a perfect square.
A number that is a perfect square and divisible by 7 is number 49 (7^2=49).
A prime number is a number that is divisible only by 1 and itself.
49 = 47 + 2 (47 and 2 are prime)
47 × 2 = 94.
Answer:
The answer would be A. 1 1/5
48/40 = 1 8/40
1 8/40 Simplify to 1 1/5
V=4/3pi(r^3)
V=4/3pi(9^3)
V=3,054 inches^3
Hope this helps!!!!!!!!!
Step-by-step explanation:
from the graph attached below:
domain of graph is the value of x for which the given function profit function p(x) is defined.
(a) the domain represents the number of years for which the outlet will earn a profit.
range of profit function defines the lowest to highest value of profit earned.
(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.
