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Ira Lisetskai [31]
3 years ago
5

If ΔMNL is rotated 180° about point N, which additional transformation could determine if ΔONP and ΔMNL are similar by the AA si

milarity postulate?
Segments OM and LP intersect at point N; triangles are formed by points LNM and ONP; line k intersects with both triangles at point N.

Reflect ONP over line k.
Reflect M'N'L' over line k.
Dilate ONP from point N by a scale factor of segment NP over segment NL.
Dilate M'N'L' from point N by a scale factor of segment NP over segment NL
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0

The answer is D because  you need to make it smaller by dilation. This leaves the last two options. D makes the most sense.

lesya [120]3 years ago
4 0

Answer:

  Dilate M'N'L' from point N by a scale factor of segment NP over segment NL

Step-by-step explanation:

Multiplying the length of N'L' by the factor NP/NL will give it the length of NP, making the dilated version of ΔM'N'L' congruent to ΔONP. This is apparently your goal.

__

Reflection over line k doesn't seem to do anything useful, and the other offered dilation is by the wrong factor. You want to ...

dilate M'N'L' from point N by a scale factor of segment NP over segment NL.

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Answer:

All of the above

Step-by-step explanation:

A whole number and integers are numbers that don't have decimals.

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A real number is any number that is not complex, which means that it has an imaginary solution or imaginary number part of it.

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3 years ago
2.a)Find the prime factorizations of 90 and 168.
balu736 [363]
90|2\\45|3\\15|3\\.\ 5|5\\.\ 1|\\\\90=2\cdot3\cdot3\cdot5\\\\168|2\\.\ 84|2\\.\ 42|2\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\168=2\cdot2\cdot2\cdot3\cdot7

100|2\\.\ 50|2\\.\ 25|5\\.\ \ 5|5\\.\ \ 1|\\\\100=2\cdot2\cdot5\cdot5\\\\126|2\\.\ 63|3\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\126=2\cdot3\cdot3\cdot7
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Use the information to solve the triangle. Round your answers to two decimal places. Hint: draw a sketch first to determine if y
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Answer:

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Step-by-step explanation:

Using angle sum of triangle, we get A = 180 - 104 - 33 = 43°

Using sin law,

b/sin104 = 18.1/sin43

b = 25.8 (3 sig. fig.)

c/sin33 = 18.1/sin43

c = 14.5 (3 sig. fig.)

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Answer:

Your answer is

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Mark my answer as brainlist . I need that urgently . Folow me for more answer.

Step-by-step explanation:

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2 years ago
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