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Ira Lisetskai [31]
3 years ago
5

If ΔMNL is rotated 180° about point N, which additional transformation could determine if ΔONP and ΔMNL are similar by the AA si

milarity postulate?
Segments OM and LP intersect at point N; triangles are formed by points LNM and ONP; line k intersects with both triangles at point N.

Reflect ONP over line k.
Reflect M'N'L' over line k.
Dilate ONP from point N by a scale factor of segment NP over segment NL.
Dilate M'N'L' from point N by a scale factor of segment NP over segment NL
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0

The answer is D because  you need to make it smaller by dilation. This leaves the last two options. D makes the most sense.

lesya [120]3 years ago
4 0

Answer:

  Dilate M'N'L' from point N by a scale factor of segment NP over segment NL

Step-by-step explanation:

Multiplying the length of N'L' by the factor NP/NL will give it the length of NP, making the dilated version of ΔM'N'L' congruent to ΔONP. This is apparently your goal.

__

Reflection over line k doesn't seem to do anything useful, and the other offered dilation is by the wrong factor. You want to ...

dilate M'N'L' from point N by a scale factor of segment NP over segment NL.

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. In the 107th Congress, the Senate consists of 13 women and 87 men. If a lobbyist for the tobacco industry randomly selects thr
brilliants [131]

Answer:

0.18% probability that they are all women

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the senators are chosen is not important, so the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes:

3 women, from a set of 13. So

D = C_{13,3} = \frac{13!}{3!(13 - 3)!} = 286

Total outcomes:

3 senators, from a set of 100. So

T = C_{100,3} = \frac{100!}{3!(100 - 3)!} = 161700

Probability;

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5 0
4 years ago
Select the correct answer from the drop-down menu.
jonny [76]

Answer:

Answer is D (got it right on plato)

Step-by-step explanation:

There are 4 of each king and queen in each standard deck of 52 cards.

4+4=8

8/52=0.1538 or 15.38%

Twenty cards are chosen from a pack of cards at random

In A there are 0 kings and 1 queen

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In B there are 2 kings and 4 queens

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In C there are 0 kings and queens

0/20=0

In D there are 2 kings and 1 queen

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D is your answer because it is the closest to the probability (0.1538 or 15.38%)

7 0
3 years ago
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