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3 years ago

Given the trinomial 5x2 − 2x − 3, predict the type of solutions.

Mathematics

1 answer:

Contact [7]3 years ago

5 0

$5x^2 - 2x - 3$

$5x^2+3x-5x-3$

$x(5x+3)-(5x+3)$

$(5x+3)(x-1)$

Factoring is the only solution.

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Use properties to evaluate - (- = {)6. O A. 1 B. c.- O D. 1 / SUBMIT

bogdanovich [222]

Answer:

-4/5

Step-by-step explanation:

first use bodmas to evaluate work on brackets then division

6 0

2 years ago

Simplify (4 √ 14 + 4 √ 10 ) ( 3 √ 7 − 4 √ 5 )

Iteru [2.4K]

Answer:

4 sqrt(2) - sqrt(70)

Step-by-step explanation:

Simplify the following:

(4 sqrt(14) + 4 sqrt(10)) (3 sqrt(7) - 4 sqrt(5))

Factor 4 out of 4 sqrt(14) + 4 sqrt(10) giving 4 (sqrt(14) + sqrt(10)):

4 (sqrt(14) + sqrt(10)) (3 sqrt(7) - 4 sqrt(5))

(sqrt(10) + sqrt(14)) (3 sqrt(7) - 4 sqrt(5)) = sqrt(10) (-4 sqrt(5)) + sqrt(10)×3 sqrt(7) + sqrt(14) (-4 sqrt(5)) + sqrt(14)×3 sqrt(7) = -20 sqrt(2) + 3 sqrt(70) - 4 sqrt(70) + 21 sqrt(2) = sqrt(2) - sqrt(70):

Answer: 4 sqrt(2) - sqrt(70)

4 0

3 years ago

X · 1 + = ___. 1 x 1 + x 2x

Aliun [14]

Answer:x · 1 + = ___.

1 + x

Step-by-step explanation:

7 0

2 years ago

The expression 4h-3 factored is

Brilliant_brown [7]

H*h*h*h - 3 because it cannot be simplified by factoring.

8 0

3 years ago

Read 2 more answers

5. A Ferris wheel at an amusement park measures 16m in diameter. It makes 3 rotations

galina1969 [7]

Following are the responses to the given points:

For point a:

$Diameter\ (d)= 16\ m\\\\$

Calculating the 3 rotations for every minute:

Calculating time for completing 1 rotation:

$1\ rotation=\frac{60}{3}= 20\ second\\\\period=20 \ second\\\\$

The standard form of the equation of the sine and cosine function is:

$y=A \sin \{ B(x-c)\} +D\\\\y=A \cos \{ B(x-c)\} +D\\\\$

Calculating the Amplitue:

$A=\frac{max-min}{2}=\frac{17-1}{2}=\frac{16}{2}=8\\\\Period=\frac{2\pi}{B}\\\\20=\frac{2\pi}{B}\\\\B=\frac{2\pi}{20}\\\\B=\frac{\pi}{10}\\\\$

Calculating the phase shift:

for $\sin$ function: $c=5$

for $\cos$ function: $c=10$

Calculating the vertical shift:

$\to D=\frac{max+ min }{2}=\frac{17+ 1}{2}=\frac{18}{2}=9\\\\y=8 \sin \{ \frac{\pi}{10}(t-5)\} +9\\\\y=8 \cos \{ \frac{\pi}{10}(t-10)\} +9\\\\$

For point b:

$y> 12\ m\\\\12=8 \sin \{ \frac{\pi}{10}(t-5)\} +9\\\\12-9=8 \sin \{ \frac{\pi}{10}(t-5)\} \\\\3=8 \sin \{ \frac{\pi}{10}(t-5)\} \\\\\frac{3}{8}=\sin \{ \frac{\pi}{10}(t-5)\} \\\\\sin^{-1}\frac{3}{8}=\frac{\pi}{10}(t-5) \\\\\frac{\pi}{10} (0.38439677)=(t-5) \\\\1.22357+5=t \\\\t=6.22357\ second\\\\t=6.22\ second\\\\\sin^{-1}\frac{3}{8}=\frac{\pi}{10}(t-5) \\\\\frac{\pi}{10} (2.7571961)=(t-5) \\\\t=8.7764+5\\\\t=13.78\ second\\\\t_2-t_1=13.7764-6.22357= 7.55283\approx 7.55\ second \\\\$

Learn more:

Rotation: brainly.in/question/39626227

5 0

3 years ago