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3 years ago

Barium magnesium Calcium what are their chemical properties

Chemistry

1 answer:

Nuetrik [128]3 years ago

7 0

Answer:

Explanation:

These are alkaline earth metals.

These are present in group two.

All have two valance electrons.

All alkaline earth metals form salt with halogens.e.g,

Mg + Cl₂ → MgCl₂

Ba + Br₂ → BaBr₂

Mg + Br₂ → MgBr₂

Ca + Br₂ → CaBr₂

They react with oxygen and form oxides of respective metal.

2Mg + O₂ → 2MgO

2Ba + O₂ → 2BaO

2Ca + O₂ → 2CaO

these oxides form hydroxide when react with water,

MgO + H₂O → Mg(OH)₂

BaO + H₂O → Ba(OH)₂

CaO + H₂O → Ca(OH)₂

With nitrogen it produced nitride,

3Mg + N₂ → Mg₃N₂

3Ba + N₂ → Ba₃N₂

3Ca + N₂ → Ca₃N₂

With acid like HCl,

Mg + 2HCl → MgCl₂ + H₂

Ba + 2HCl → BaCl₂ + H₂

Ca + 2HCl → CaCl₂ + H₂

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Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

3 0

3 years ago

Convert the scientific notation to a decimal number. Type the correct answer in the box. 4 × 10-5 cm = cm

MakcuM [25]

Answer:

$4 * 10^{-5}cm = 0.00004cm$

Explanation:

Given

$4 * 10^{-5}cm = [\ ]cm$

Required

Solve

Apply law of indices

$4 * \frac{1}{10^5}cm = [\ ]cm$

Evaluate 10^5

$4 * \frac{1}{100000}cm = [\ ]cm$

$4 * 0.00001cm = [\ ]cm$

$0.00004cm = [\ ]cm$

Hence:

$4 * 10^{-5}cm = 0.00004cm$

3 0

3 years ago

A solution of toilet bowl cleaner has PH of 13 the solution is?

AlladinOne [14]

The solution is an alkali.

Usually with the pH value range of 14, substances with pH 7 can be called neutral. Meanwhile substances lower than pH 7 are acids, the lower the pH is, the more acidic it is. Such as cola, it has a pH 2, which is very acidic.
In opposite, the substances with pH over 7 are called alkalis. Again, the larger the pH value is, the more alkaline it is. So pH 13 is a strong alkaline therefore it it corrosive and can clean the toilet well.

8 0

3 years ago

30) When ionic bonds are formed, metallic atoms tend to

Strike441 [17]

Answer:

B is the answer

Explanation:

7 0

3 years ago

At what temperature will a balloon have a volume of 6.08 L if the temperature is 41.0 ℃ when its volume is 4.87 L? in kelvin

Alex Ar [27]

Answer:

T₂ = 251.6 K

Explanation:

Given data:

Initial temperature = 41°C

Initial volume = 4.87 L

Final volume = 6.08 L

Final temperature = ?

Solution:

Initial temperature = 41°C (41+273.15 = 314.15 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ /V₁

T₂ = 4.87 L × 314.15 K / 6.08 L

T₂ = 1529.9 L.K / 6.08 L

T₂ = 251.6 K

4 0

4 years ago