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marishachu [46]
3 years ago
8

Determine the chemical formulas for the two compounds below. (Carbon, Hydrogen, and Oxygen).

Chemistry
1 answer:
tester [92]3 years ago
4 0
Remember that any intersection of lines is a C, and that the number of hydrogens attached are the necessary to complet the 4 bonds.

1) CH3 - CH (OH) - CH (CH3) -CH3

2) CH3 - O - CH(CH3)-CH2 - CH3

I have used the parenthesis to indicate that the radical inside is in other branch, bonded by a single line -
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Answer:

d. oxygen is a pure substance and rocks are mixtures

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Which segement of the heating curve shown above represents an increase in the potential energy, but no change in the kinetic ene
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Identify the element symbol<br> 1s22s22p63s23p64s23d104p65s24d5
madam [21]

Answer:

Tc

Explanation:

You just have to follow the rows with the exponents. Just remember that when we get to d, the number in the front is a period lower. Hope this helps!

5 0
1 year ago
monatomic ion with a charge of +2 has an electronic configuration of 1s22s22p63s23p6. This ion is a(n) . What is the chemical sy
Debora [2.8K]

Answer: The ion is Ca^{2+}. The chemical symbol of the noble gas this ion is isoelectronic with Kr.

Explanation:

The given electronic configuration is,

M^{2+}:1s^22s^22p^63s^23p^6

The number of electrons = 2 + 2 + 6 + 2 + 6 = 18 electrons

As the ion has a charge of +2 , that means it has lost two electrons so the the neutral element will have 2 more electrons i.e 18+2 = 20. The element has atomic number of 20 and the element will be Calcium with electronic configuration of

M: 1s^22s^22p^63s^23p^64s^2

Thus the symbol of ion is Ca^{2+}. the nearest noble gas with 18 electrons is Krypton with symbol Kr.

3 0
4 years ago
Which of the following is unchanged at the end of the CNO cycle?
Musya8 [376]

Answer:

The correct option is: A. carbon-12

Explanation:

The CNO cycle, the abbreviation for the carbon-nitrogen-oxygen cycle, is a catalytic cycle by which the stars produce helium from elemental hydrogen, via a series of nuclear fusion reactions.

This cycle involves the fusion of four protons with carbon (_{6}^{12}\textrm{C}), nitrogen isotope (_{7}^{13}\textrm{N}), and oxygen isotope (_{8}^{15}\textrm{O}), to give an alpha particle and two electron neutrinos and positrons.

The reaction involves the regeneration of carbon (_{6}^{12}\textrm{C}) nucleus in the last step.

_{6}^{12}\textrm{C} → _{7}^{13}\textrm{N} → _{6}^{13}\textrm{C} → _{7}^{14}\textrm{N} → _{8}^{15}\textrm{O} → _{7}^{15}\textrm{N} → _{6}^{12}\textrm{C}

3 0
3 years ago
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