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lana66690 [7]
3 years ago
14

What is the percent yield made if 3.9 grams of a substance were made experimentally while you calculated 3.6 grams of substance

using stoichiometry
Chemistry
1 answer:
Alenkasestr [34]3 years ago
5 0

Percent yield is 108.3%

<u>Explanation:</u>

Percent yield is the ratio of experimental yield and the theoretical yield multiplied by 100.The expression for the percent yield is given as,

Percent yield = $\frac{actual yield}{theoretical yield}\times100

It is given that the experimental or actual yield is 3.9 g and the theoretical yield calculated using stoichiometry is 3.6 g, then the percent yield is calculated as,

Percent yield = $\frac{3.9}{3.6}\times100 = 108.3

So the percent yield is 108.3%.

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Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

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P_1 = initial pressure of gas = 0.947 atm

P_2 = final pressure of gas = 0.987 atm

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T_1 = initial temperature of gas = 25^0C=(25+273.15)K=298.15K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

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The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

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