Answer : The molarity after a reaction time of 5.00 days is, 0.109 M
Explanation :
The integrated rate law equation for second order reaction follows:
where,
k = rate constant =
t = time taken = 5.00 days
[A] = concentration of substance after time 't' = ?
= Initial concentration = 0.110 M
Now put all the given values in above equation, we get:
Hence, the molarity after a reaction time of 5.00 days is, 0.109 M
Answer:
Explanation:
Hello!
In this case, since the average rate of reaction is computed as a change given by:
In such a way, given the concentrations at the specified times, we plug them in to obtain:
Whose negative sign means the concentration decreased due to the decomposition.
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Answer: Oxidation number of chlorine in potassium chlorate...
so, oxidation state of chlorine in potassium chlorate is +1. and yea!!
Explanation: hope this help
In this item, I supposed, that we are determine the molar fraction of oxygen and carbon dioxide in the sample. This can be done by dividing their respective partial pressures by the total pressure of the sample.
O2 : mole fraction = (100.7 mmHg) / (763.00 mmHg) = 0.13
CO2 : mole fraction = (33.57 mmHg) / (763.00 mmHg) = 0.044
Answers: O2 = 0.13
CO2 = 0.044
Answer:
See explanation
Explanation:
A net ionic equation shows only the chemical species that are involved in a reaction, while a complete ionic equation also includes the spectator ions(Khan Academy).
From the species shown in the image we can write the molecular equation, ionic equation and net ionic equation and also identify the spectator ions.
Chemical equation: KX + BY --------> BX + AY
Ionic Equation; X^- + A^+ + B^+ + Y^- -----> BX + A^+ + Y^-
Spectator ions; A^+ and Y^-
Net Ionic Equation; X^- + B^+ ------> BX