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3 years ago

The triangles are similar. The area of the larger triangle is 1200 cm?

Mathematics

2 answers:

Wittaler [7]3 years ago

7 0

Answer:

I would say 75cm^2.

borishaifa [10]3 years ago

4 0

Answer:

75 cm^2

Step-by-step explanation:

We have the lengths of two corresponding sides. The scale factor from the large triangle to the small triangle is 16/64 = 1/4. Each side of the smaller triangle is 1/4 times the length of the corresponding side of the large triangle.

For the areas, the scale factor is the square of the scale factor of the lengths. Area scale factor = 1/4^2 = 1/16.

The area of the small triangle is 1/16 the area of the large triangle.

area of small triangle = (area of large triangle) * (area scale factor)

area of small triangle = 1200 cm^2 * 1/6 = 1200 cm^2/16

area of small triangle = (1200 cm^2)/16 = 75 cm^2

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If the volume of a sphere inscribed in a cubic box is 36pi, find the surface area of the box

Kruka [31]

Answer:

Surface area of the cube = 216 square units

Step-by-step explanation:

Let the length of a side of a cube = x unit

Diameter of the sphere inscribed in this cube = length of a side of the cube

Volume of the sphere = $\frac{4}{3}\pi r^{3}$

Where r = radius of the sphere = $\frac{x}{2}$ units

36π = $\frac{4}{3}\pi (\frac{x}{2})^{3}$

36π = $\frac{4x^{3}\pi }{24}$

36×24 = 4x³

x = $\sqrt[3]{\frac{36\times 24}{4} }$

x = 6 units

Length of a side of the cube = 6 units

Surface area of the cube = 6×(Side)²

= 6×(6)²

= 216

= 216 square units

3 0

3 years ago

Ariel was told the x intercept and the y intercept of a line with a positive slope. Yet, it was impossible for Ariel to find the

alexdok [17]

A line has the following standard equation form:

y = m x + b

where m is the slope and b is the y intercept

So if Ariel cannot find the slope, then this would only mean that m = 0, there is no slope. And hence the line is either a straight vertical line or straight horizontal line.

Answer:

<span>There is no slope</span>

8 0

3 years ago

Given that WA = 5x – 8 and WC = 3x + 2, find WB. A. WB = 5 B. WB = 8 C. WB = 10 D. WB = 17

rodikova [14]

The rest of the question is the attached figure.
============================================
Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
And AY = YB ⇒⇒⇒ ∴ WA² = YB² + YW² → (1)
Δ BYW a right triangle at Y ⇒⇒⇒ ∴ WB² = BY² + YW² → (2)
From (1) , (2) ⇒⇒⇒ ∴ WA = WB →→ (3)
Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
And CX = XB ⇒⇒⇒ ∴ WC² = XB² + XW² → (4)
Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW² → (5)
From (4) , (5) ⇒⇒⇒ ∴ WC = WB →→ (6)
From (3) , (6)
WA = WB = WC
given ⇒⇒⇒ WA = 5x – 8 and WC = 3x + 2
∴ <span> 5x – 8 = 3x + 2</span>
Solve for x ⇒⇒⇒ ∴ x = 5
∴ WB = WA = WC = 3*5 + 2 = 17

The correct answer is option D. WB = 17