All categories

2 years ago

(04.01)Which unit rate is the lowest price per ounce?

Mathematics

1 answer:

REY [17]2 years ago

7 0

Choice a is a good one by the way

You might be interested in

According to the fundamental theorem of algebra, how many zeros does the function f(x) = 15x17 + 41x12 + 13x3 − 10 have?

liberstina [14]

The fundamental theorem of algebra states that a polynomial of degree has exactly n roots (including complex and multiple).
The degree of a polynomial is the highest (non-negative) exponent of the polynomial, in this case is 17 from the term 15x^17.

3 0

2 years ago

Read 2 more answers

What is the product of 7.951x 1.314

gladu [14]

Answer:

10.447614

Step-by-step explanation:

The product of 7.951x 1.314 is 10.447614.

7 0

3 years ago

A tv that normally cost $800

sukhopar [10]

what is the question it might be an Sony-75"

6 0

2 years ago

What is the measure of angle Z?

Iteru [2.4K]

Answer:

sum of exterior angles of polygon = 360°

therefore,

z = 360 - (105+145)

z = 360 - 250

z = 110°

3 0

3 years ago

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

2 years ago

Read 2 more answers