Using proportions, considering the weight of each bar and the ratio, it is found that the ship is carrying 52 gold bars.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three.
Each bar weighs 5 kg, and the total weight is of 600 kg, hence the number of bars is given by:
n = 600/5 = 120.
The proportion of gold bars is given by:
p = 13/(13 + 17) = 13/30
Hence, out of 120 bars, the number of gold bars is given by:
nG = 120 x 13/30 = 4 x 13 = 52.
More can be learned about proportions at brainly.com/question/24372153
#SPJ1
Answer:
The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )
I.e option D
Step-by-step explanation:
Given equation as :
x² - 8 x + 41 = 0
For quadratic equation ax² + b x + c = 0
The value of x =
∴ For equation x² - 8 x + 41 = 0
Or, x =
Or, x = 
Or, x = 
∴ x = ( 4 + 2 i ) , ( 4 - 2 i )
Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )
I.e option D Answer
6 | 16 is the correct answer I believe
Answer:
The probability is 0.508 = 50.8%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.0525 g.
This means that 
If 1 candy is randomly selected, find the probability that it weighs more than 0.8535 g.
This is 1 subtracted by the pvalue of Z when X = 0.8535. So



has a pvalue of 0.492
1 - 0.492 = 0.508
The probability is 0.508 = 50.8%.