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guajiro [1.7K]
3 years ago
5

Estimate the length of the radius if the area of the circle is 54 ft2.

Mathematics
1 answer:
jekas [21]3 years ago
4 0
Area = pi(r^2)
54 = pi(r^2)
54/pi= r^2
sqrt (54/pi) = r
4.15 is approximately the radius
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Step-by-step explanation:

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A ship is carrying gold bars and silver bars in the ratio 13:17. The ship's load
andreyandreev [35.5K]

Using proportions, considering the weight of each bar and the ratio, it is found that the ship is carrying 52 gold bars.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Each bar weighs 5 kg, and the total weight is of 600 kg, hence the number of bars is given by:

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4 0
2 years ago
Solve for x in the equation X2-8x+41 = 0 -
djverab [1.8K]

Answer:

The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D  

Step-by-step explanation:

Given equation as :

x² - 8 x + 41 = 0

For quadratic equation  ax² + b x + c = 0

The value of x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

∴ For equation x² - 8 x + 41 = 0

Or,                x = \frac{8\pm \sqrt{-8^{2}-4\times 1\times 41}}{2\times 1}

Or,                x = \frac{8\pm \sqrt{-100}}{2}

Or,                x = \frac{8\pm 10i}{2}

∴                  x = ( 4 + 2 i ) , ( 4 - 2 i )

Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D     Answer

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3 years ago
Some values of the linear function 'f' are shown in the table what is the value of 3?
Monica [59]
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3 years ago
The weights of a certain brand of candies are normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.
aleksandr82 [10.1K]

Answer:

The probability is 0.508 = 50.8%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.0525 g.

This means that \mu = 0.8544, \sigma = 0.0525

If 1 candy is randomly​ selected, find the probability that it weighs more than 0.8535 g.

This is 1 subtracted by the pvalue of Z when X = 0.8535. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.8535 - 0.8544}{0.0525}

Z = -0.02

Z = -0.02 has a pvalue of 0.492

1 - 0.492 = 0.508

The probability is 0.508 = 50.8%.

8 0
3 years ago
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