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Alenkinab [10]
3 years ago
6

A bag with

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0
There is a greater possibility for choosing the white marble since there are more of them than the black and grey marbles.
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Solve for y<br> -1/2=6/5y-2/3
ella [17]
5/36 would be it I say
6 0
3 years ago
Read 2 more answers
1 to the tenth power
dmitriy555 [2]
Answer: 1

Explanation:

1 to any power will always be 1
8 0
3 years ago
Read 2 more answers
Lara solved an equation incorrectly, as shown below:
son4ous [18]

We have been given the steps to solve the equation as

Step 1: 2x = 18

Step 2: x = 18 − 2

Step 3: x = 16

There is an error in step 2.

We have 2x=18

x is in multiplication with 2. So in order to get rid of 2 from the left hand side, we perform opposite operation of multiplication i.e. division.

So we must divide both sides by 2.

Therefore, A is the correct option.

A) She did not divide 18 by 2.

8 0
3 years ago
Read 2 more answers
Find the derivative of f(x) = 6/x at x = -2. select one: a. 6 b. 3/2 c. -3/2 d. -6
Ivenika [448]
F(X) = 6/X

F(X) = 6 • 1/X

F(X) = 6 • x^-1

F(X) = 6x^-1

F'(X) = 6 • d(x^-1)/dx

F'(X) = 6 • -1x^-1-1

F'(X) = 6 • -1x^-2

F'(X) = -6x^-2

F'(X) = -6/x^2
F'(-2) = -6/(-2)^2
F'(-2) = -6/4
F'(-2) = -3/2

The solution would be C. -3/2.
5 0
2 years ago
I'm new to this and I dont really understand this
agasfer [191]

Answer:

So starting off with 1a f(4)

We simply substitute x with 4 for the function

f(4)=2(4)-5

f(4)=8-5

f(4)=3

Next 1b, here it's a little different since you have to multiply the functions I think ( please correct me if I'm wrong).

gf(4), basically means functions g and f are being multiplied and their variables are being substituted with 4.

g(4)=4^2+3

g(4)=16+3

g(4)=19

and we also know from before that f(4)=3, so we'll do 19 times 3 which is 57

For the next two, I may be wrong, but I'm still going to try:

anything to the power of a negative is a fraction so for f^-1(x)=2x-5 we'll have 1/f(x)=x/2+5/2

And then for g^-1, we'll have 1/g(x)=\sqrt{x-3}  \sqrt{x-3}

Hope I helped :)

5 0
2 years ago
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