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2 years ago

Lashaya decides to jog 8 miles. She is only able to jog 5/16 that distance. Write the distance

Mathematics

1 answer:

Novay_Z [31]2 years ago

6 0

Answer:

The distance is $2.5\ miles$

Step-by-step explanation:

Let

x------> the distance

we know that

To find the distance, multiply the total distance of 8 miles by 5/16

$x=8(\frac{5}{16})=\frac{5}{2}=2.5\ miles$

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Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

2 years ago

alabama power came by my house that i just bought and installed a new wire support for one of the telephone poles on the propert

PolarNik [594]

Answer:

30 feets

Step-by-step explanation:

subtrqct 55-25 = 30

8 0

2 years ago

Which set of transformations would prove ALMN - APQR?

Gnoma [55]

Answer:

2 I think

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The endpoints of CD are C(3,−5) and D(7, 9).<br> The coordinates of the midpoint M of CD are?

Nutka1998 [239]

Answer:

M(5,2)

Step-by-step explanation:

We use the midpoint rule:

$( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )$

We just have to find the arithmetic mean of the x and y-coordinates.

The endpoints of CD are given as C(3,−5) and D(7, 9).

We substitute these values to get:

$( \frac{7 + 3}{2}, \frac{9 + - 5}{2} )$

$( \frac{10}{2}, \frac{4}{2} )$

$(5, 2)$

Therefore the coordinates of the midpoint M of CD are (5,2)

3 0

3 years ago

See image for question and answer choices

Alexxx [7]

Answer:

Step-by-step explanation:

So, lets remember a few things first.

#1: The formula for finding the answer is A^2+B^2=C^2

#2: A is the opposite side, B is the adjacent side, and C is the hypotenouse side.

Now lets plug in what we already know, and see if we canf igure out the annswer:

Now I am going to stop us here. This is your equation that will find the answer. In your question, they use x^2, A^2 is a variable you can use instead. But looking at this, answer B and my equation I wrote above are exactly the same.

If you want, here is how I further solved it, this might give you a better grasp on what to do for future problems:

Ok, not too bad, the A is the unkown value, which is the opposite side.

Now, how do we figure this out? Well, we just need to sovle for A.

To do this, lets clean up our equation by first sqauring all the values(except for the unkown):

A^2+144=169

Ok, that looks better, now lets just subtract the adjeacent side(b), which is 144, from the hypotenouse side(c), which is 169.

This will now look like:

A^2=25(169-144=25)

Ok, just one more step to go. Just square root both sides of the equation, this way, we will get ride of the ^2 on A(opposite side), and get A alone.

( $\sqrt{A^2}=A$ )=( $\sqrt{25}=5$ )

A=5

This is your answer.

5 0

2 years ago