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2 years ago

3. a) The dimensions of your game cover are 20 cm x 15 cm. However, you need to have a strip of

Mathematics

2 answers:

DaniilM [7]2 years ago

6 0

20cm×15 cm =300

/100 = 0.32

yuradex [85]2 years ago

5 0

9514 1404 393

Answer:

1.5 cm

Step-by-step explanation:

All areas are in cm^2. For a width w, the border will have an area equal to the product of its centerline length and its width:

border area = 2((20-w) +(15-w))·w = w(70 -4w)

This area is 32% of the total cover area, so is ...

0.32(20)(15) = 96

Equating these expressions for the area gives ...

96 = 70w -4w^2

w^2 -17.5w = -24 . . . . . divide by -4

w^2 -17.5w +8.75^2 = -24 +8.75^2 . . . . . complete the square

(w -8.75)^2 = 52.5625 . . . . simplify

w -8.75 = ±√52.5625 = ±7.25

A border width only makes sense if it is between 0 and 7.5 cm, so the appropriate value for w is ...

w = 8.75 ± 7.25 . . . . . . . . . add 8.75

w = 8.75 -7.25 = 1.50 . . . . . the solution w=16 makes no sense

The border width is 1.5 cm.

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Please help me I would also like an explanation

Tasya [4]

Answer:

k = 45*

2k = 90*

Step-by-step explanation:

K will be the same as the 45* degrees, as it is across from it.

2k is twice k, which is 90*.

45* + 45* + 90* = 180*

Good luck!

4 0

3 years ago

Nethan made 8 rose bouquets and 6 daffodil bouquets. Nethan only has enough flowers to make at most 20 rose or daffodil bouquets

Solnce55 [7]

Answer:

Nethan made 8 rose bouquets and 6 daffodil bouquets.

Nethan only has enough flowers to make at most 20 rose or daffodil bouquets total.

Let x represents the number of more rose bouquets.

Let y represents the number of more daffodil bouquets.

The maximum bouquets that can be made = 20

And the number of bouquets made are = 14

So, additional bouquets are = $20-14=6$

In equation form we can show like :

$x +y= 6$

or $y=6 -x$

or $x=6- y$

Putting values of x as 0,2,4 and 6 we get:

When x = 0 then y = 6

When x = 2 then y = 4

When x = 4 then y = 2

When x = 6 then y = 0

You can see the graph attached.

3 0

3 years ago

In the accompanying diagram, line n is parallel to

mote1985 [20]

Here too same procedure
4) 156 is the answer

4 0

2 years ago

9. A pyramid has a square base with an area

Vlad [161]

Answer:

48 ft

Step-by-step explanation:

A = 144ft² = l²

144 = l²

l = √144

l = 12 ft

P = 4l

= 4×12ft

= 48 ft

4 0

3 years ago

Which of the following statements are true? Select all that apply.

Tom [10]

Answer: The statements in options 2 and 4 are true.

Explanation:

The LCM of two numbers is the smallest number that is multiple of both numbers.

The factor of 8 and 12 are,

$8=2\times 2\times 2$

$12=2\times 2\times 3$

Since 2 and 2 are common in both but 2 and 3 are not same, therefore the L.C.M. of 8 and 12 is,

$L.C.M.(8,12)=2\times 2\times 2\times 3=24$

Therefore the statement in option 1 is incorrect.

The factor of 6 and 9 are,

$6=2\times 3$

$9=3\times 3$

Since 3 is common in both but 2 and 3 are not same, therefore the L.C.M. of 6 and 9 is,

$L.C.M.(6,9)=2\times 3\times 3=18$

Therefore the statement in option 2 is correct.

The factor of 11 and 4 are,

$11=1\times 11$

$4=2\times 2$

Since all factor are different, therefore the L.C.M. of 11 and 4 is,

$L.C.M.(11,4)=1\times 11\times 2\times 2=44$

Therefore the statement in option 3 is incorrect.

The factor of 9 and 10 are,

$9=1\times 9$

$10=2\times 5$

Since all factor are different, therefore the L.C.M. of 9 and 10 is,

$L.C.M.(9,10)=1\times 9\times 2\times 5=90$

Therefore the statement in option 4 is correct.

4 0

3 years ago