We have a line y = 1/3x -6
We want a line that is perpendicular to this line
Perpendicular lines have slopes that multiply to -1
1/3 * m = -1
3 * 1/3 *m = -1 * 3
m = -3
The slope of the perpendicular line is -3
y = mx+b where m is the slope and b is the y intercept
y = -3x+b
We have a point on the line ( 7 ,-23)
Substitute this point into the equation
-23 = -3(7)+b
-23 = -21+b
Add 21 to each side
-23+21 = -21+21+b
-2 = b
y = -3x-2
In slope intercept form, the line perpendicular passing through (7,-23) is
y = -3x-2
Answer:
x=7
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
6(x−1)=−2x+50
(6)(x)+(6)(−1)=−2x+50(Distribute)
6x+−6=−2x+50
6x−6=−2x+50
Step 2: Add 2x to both sides.
6x−6+2x=−2x+50+2x
8x−6=50
Step 3: Add 6 to both sides.
8x−6+6=50+6
8x=56
Step 4: Divide both sides by 8.
8x
/8
=
56
/8
x=7
Answer:
22.45
Step-by-step explanation:
Answer:the area is 28.27
Step-by-step explanation:
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