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Oxana [17]
2 years ago
12

If the point (x, y) is in Quadrant IV, which of the following must be true?

Mathematics
1 answer:
gayaneshka [121]2 years ago
4 0

Answer:

Any coordinate point with (positive x, negative y)

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Express sin110 as ratio of acute angle
lesya [120]

Answer:

sin70°

Step-by-step explanation:

Given sin110° where 110° is an obtuse angle in the second quadrant.

The related acute angle in the first quadrant is 180° - 110° = 70°

Thus

sin110° = sin70°

8 0
3 years ago
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
Can you help me plsssssssssssss
Anvisha [2.4K]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
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Pls do some research but can I bring a bearded dragon on a 12 hour car trip without any heath issues happening?​
creativ13 [48]

Answer:

after doing a little bit of research. NO your bearded dragon will not be affected as long as you feed it and keep it on a level surface so the enclosure it's in does not tip at all other than that it will be perfectly fine.

5 0
3 years ago
The hexagon GIKMPR and FJN are regular. The dashed line segments form 30 degree angles.
Cerrena [4.2K]
We know that for each triangle made up by dashed line segment forms 30° angles, so, for example, ∠GOH is 30° and then ∠HOI is 30°

Rotating the shape 240° around the centre is the same as counting in 30°

The triangle GOH will first fit the triangle HOI then triangle IOJ and so on until it has completed 8 times 30° turn. Its final position is shown in the diagram below

4 0
3 years ago
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