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Elan Coil [88]
3 years ago
12

Os curtos de uma prefeitura com a área da educação aumentaram cerca de 18%. Considerando que a prefeitura destinava a quantia de

R$900.000,00 qual deverá ser o novo valor destinado para a educação?
Mathematics
1 answer:
Semmy [17]3 years ago
8 0

18% em forma decimal é 0.18.

Porque isto é um aumento de valor, adicionamos a percentagem original aos 18%.

1.18 é o multiplicador que necessitamos.

Agora:

900,000*1.18=1,062,000

A resposta é R$1,062,000.

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34kurt
So to find how much Ruben will make if he works 4 hours a day as a cashier and 3 hours a day as a waiter for 5 days per week first we'll work on his cashier job. So he makes 4$ an hour as a cashier and her works 4 hours every day for 5 days, multiply 4 by 4 and you'll get 16, so he makes 16 dollars per day as a cashier. now that we know how much he makes a day we simply have to multiply 16 by 5 since he works for 5 days every week. 16*5 is 80, so Ruben makes 80 dollars working 4 hours a day for 5 days. Now we move onto his waiter job. he makes 5.50 an hour as a waiter and her works 3 hours a day. So we multiply 3 by 5.50 to get 16.5. Next, we multiply 16.5 by 5 since he also works 5 days a week as a waiter. 16.5*5 is equal to 82.5. now we add 82.5 and 80 to get 162.5. SO Ruben makes 162.5$ working both jobs 5 days a week 
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3 years ago
18 x - 54 xy + 36y please help me send the answer As soon as possible
lubasha [3.4K]

18(X-3xy+2y)

Step-by-step explanation:

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2 years ago
A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6
ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

<u>Now, According to question</u>

The population of bacteria after 6 days = initial population × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, f = i × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, f = 1000 × (1+\dfrac{\textrm 15}{100})^{\textrm 6}

Or, f = 1000 × (1.15)^{6}

Or, f = 1000 × 2.31306

∴  f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06  Answer

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