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3 years ago

What is 12.72 divided by 3.6

1 answer:

5 0

It is 3.53333333333, this can go on forever so all you need to do is but a line about the first 3 to symbolize that this will continue on.

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QUESTION ON PIC THANK YOU FOR ANSWERING

almond37 [142]

Answer: 33.096 lbs

Step-by-step explanation:

Multiply percentage of fat by weight

.197 x 168 = 33.096

3 0

2 years ago

What are the side lengths of the rectangle area 40 perimeter 26

shusha [124]

Recall the formula for finding the area of a rectangle:

Area = Length × Width

Recall the formula for finding the perimeter of a rectangle:

Perimeter = 2 ( Length + Width )

Given in your problem:
Area = 40 sq. units
Perimeter = 26 units

Required to solve for:
Length (L) and width (W)

• First, substitute the given to the formula:

Area = Length x Width
  40 = L × W   ⇒ equation number 1

Perimeter = 2 ( Length + Width )
26 = 2 ( L + W ) ⇒ equation number 2

• Simplifying equation number 2,
13 = L + W

• Rearranging the equation,

L = 13 - W ⇒ equation 3

Substituting equation 3 from equation 1:

( equation 1 ) 40 = (L)(W)
( equation 3 ) L = 13 - W
   40 = (13 - W) (W)
40 = 13W - W²
( regrouping ) W² - 13W + 40 = 0
( factoring ) (W - 8) (W - 5) = 0
W - 8 = 0 ; W - 5 = 0
   W = 8 ; W = 5

Therefore, there are 2 possible values for the width of the rectangle. It can be 8 units or 5 units.

• Now to solve for the length of the rectangle, substitute the two values of width to equation 3.

(equation 3) L = 13 - W
for W = 8   ⇒ L = 13 - 8
L = 5 units

for W = 5   ⇒ L = 13 - 5
L = 8 units

3 0

2 years ago

The vertex form of an equation is y = 3(x + 2)2 + 1. What is the standard form of the

Zigmanuir [339]

Answer:

y=3x^2+12x+13

a=3

b=12

c=13

3 0

3 years ago

What is the coefficient of x in expression of 5mx

baherus [9]

⇒

Coefficient of this expression is 5 only.

- BRAINLIEST answerer

3 0

2 years ago

Suizi bought 5 packages of M&M and each package contained 18 candy pieces. She opened the frist package and counted 4 green

masha68 [24]

<h3>There are fewer than 14 green pieces in all 5 packages. </h3>

Step-by-step explanation:

Here, the given question is incomplete.

Suzi bought 5 packages of M&M's, and each package contained 18 candy pieces. She opened the first package and counted 4 green pieces. She then counted 3 green pieces in the second package. Which statement about the candy pieces in the remaining packages is best supported by this information?

A. There are fewer than 14 green pieces in all 5 packages.

B. There are between 15 and 20 green pieces in all 5 packages.

C. There are at least 25 green pieces but no more than 50 in all 5 packages. D. There are more than 50 green pieces in all 5 packages.

Now, here given:

The number of packages of M & M purchased = 5 packets

The number of candies in each packet = 18

The number of green candies in first pack = 4

The number of green candies in second pack = 3

Now as we can see the number of green candies in decreasing by 1 in number as we open more packets.

So, according to this pattern:

The number of green candies in third pack = 2

The number of green candies in fourth pack = 1

And the fifth pack will have NO green candies.

So, the total number of green candies in all 5 packets combined

= 4 + 3+ 2 + 1 + 0

= 10 green candies

⇒ There are fewer than 14 green pieces in all 5 packages.

5 0

3 years ago