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Nezavi [6.7K]
3 years ago
6

What is 12.72 divided by 3.6

Mathematics
1 answer:
Contact [7]3 years ago
5 0
It is 3.53333333333, this can go on forever so all you need to do is but a line about the first 3 to symbolize that this will continue on.
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Kyra is using rectangular tiles of two types for a floor design. A tile of each type is shown below: Two rectangular tiles, rect
Rudiy27
Since there is no picture shown, I just plotted the given data points myself. That is shown in the attached picture. The blue rectangle is rectangle PQRS while the orange one is rectangle JKLM. I believe there are some choices for this question but you forgot to include. Nevertheless, I will give my observations from the given figure. 

The tile PQRS is bigger than tile JKLM. A rectangle is a two-dimensional shape that has two sets of equal parallel planes. Thus, its area is equal to the length multiplied by its width.

tile PQRS = (9-5)*(12-7) = 20 units²
tile JKLM = (6-4)*(10-5) = 10 units²

Tile PQRS is larger by 10 units².


8 0
3 years ago
Consider the triangle.
lbvjy [14]

Answer:

It is 26cm.

Step-by-step explanation:

Do  Pythagorean theorem, a^2+b^2=c^2

So 24^2+10^2,

576+100,

676.

Next, we square root it to simplify c^2 to get c by itself

(sqrt)676,

26.

7 0
2 years ago
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Decide whether the table could represent a proportional relationship. If the relationship could be proportional, what would be t
Feliz [49]

Answer:

a) non-proportional/ constant rate: 3

b) non-proportional/ constant rate 3

Step-by-step explanation:

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2 years ago
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Max was on vacation twice as long as Jerad and half as long as wesley the boys were on vacation for a total of 3 weeks of long o
netineya [11]
Jerrad has a 3-day vacation, Max has a 6-day vacation, and Wesley's vacation is 12 days
3 0
3 years ago
I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5
Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}

Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
=\frac{3x}{\sqrt{3-3x^2}}

Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
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