Answer:
Rate of change of the diameter is equal to 0.053cm/min
Step-by-step explanation:
A snowball is of the shape of a sphere
Surface area of Sphere (S)= ![4*pi*R^2](https://tex.z-dn.net/?f=4%2Api%2AR%5E2)
Rate of change of surface area
dS/dt = -4![cm^2/min](https://tex.z-dn.net/?f=cm%5E2%2Fmin)
the negative sign indicates the surface area is decreasing.
Radius = d/2 where d represents diameter
using this is the surface area equation
S = ![4*pi*(d/2)^2](https://tex.z-dn.net/?f=4%2Api%2A%28d%2F2%29%5E2)
= ![pi*d^2](https://tex.z-dn.net/?f=pi%2Ad%5E2)
dS/dt = 2*pi*d*d(d)/dt
4 = 2*pi*d*(d)/dt
d(d)/dt = 2/12*pi=
cm/min
so the rate of change of the diameter is equal to 0.053cm/min
Answer:
= -5
Step-by-step explanation:
1-6=5
1-6
{Subtract the numbers:} 1-6=-5
= -5
Answer:
7 & 8
Step-by-step explanation:
= 7.7459666924148337703585307995648
Therefore, it lies between the whole numbers 7 & 8.
Hope this helps :)
Answer: 0.16
Step-by-step explanation:
You can reduce this fraction
8/50
4/25 = 4 ÷ 25 = 0.16
I hope this helps! c: