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3 years ago

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Find the range of the function r(x) for the given domain. r(x) = 2(2*)+3 D = {-1,0,1,3}

1 answer:

e-lub [12.9K]3 years ago

7 0

Answer: R = {4, 5, 7, 19}

<u>Step-by-step explanation:</u>

Domain represents the x-values.

Range represents the y-values.

Insert the values of the domain into the given equation.

$\begin {array}{c|l|c}\underline{\ x\ }&\underline{\ 2(2^x)+3 =\ }&\underline{\ r(x)\ }\\ -1&2(2^{-1})+3=&4\\0&2(2^0)+3=&5\\1&2(2^1)+3=&7\\3&2(2^3)+3=&19\\\end{array}$

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2/3 is what percent of 1/4?

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So if we take 1/4 to be the 100%, what is 2/3 in percentage off of it then?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{4}&100\\\\
\frac{2}{3}&p
\end{array}\implies \cfrac{\frac{1}{4}}{\frac{2}{3}}=\cfrac{100}{p}\implies \cfrac{1}{4}\cdot \cfrac{3}{2}=\cfrac{100}{p}\implies \cfrac{3}{8}=\cfrac{100}{p}
\\\\\\
p=\cfrac{8\cdot 100}{3}\implies p=\cfrac{800}{3}\implies p=266\frac{2}{3}\implies p\approx 266.\overline{66}$

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Compute the following: 325 C1

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A spinner has 5 equal sections labeled 1 through 5. The bar graph shows the results of spinning the spinner 100 times. Which sta

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Step-by-step explanation:

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June made a design with 6 equal tiles. One tile is yellow, 2 tiles are blue,and three tiles are purple. What fraction of the til

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Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

Lelechka [254]

Answer:

a)

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

b)

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

a)

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

b)

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

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3 years ago