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RideAnS [48]
3 years ago
13

If LaTeX: z_{obt}z o b t= +2.21, do you reject LaTeX: H_0H 0 or fail to reject LaTeX: H_0H 0 using a one-tailed test in the uppe

r tail with α = .05? Why do you make that choice? Note: Be sure to type in the correct answer in the space provided here.
Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

Reject the null hypothesis

Step-by-step explanation:

From the question we are told that

   The test statistic is  z_{obt} =  +2.21

    The level of significance is  \alpha  =  0.05

Given that this a one tailed in the upper tail then from the z table the area under the normal  curve to the right  corresponding to z_{obt} =  +2.21 is

      P( Z >  2.21) = 0.013553

So the p-value  is

       p-value  =  P( Z >  2.21) = 0.013553

From the values obtained we see that   p-value < \alpha  hence

The decision rule

 Reject the null hypothesis

     

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A package of twelve cans of the black beans cost $6.84. What is the cost of three cans of black beans?
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Answer:

$1.66

Step-by-step explanation:

First you need to divide $6.74 by 12 then you will get $0.55. Next you need to multiply $0.55 by 3 cans of black beans and you should get $1.66.

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3 years ago
Hi I’m back again and I need help with this question on my daily common core review sheet. Thanks a lot, answer this and you get
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Answer:

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Step-by-step explanation:

That's the biggest number

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Large pool equipment sets cost $1,042. Small pool equipment sets cost$907. How much does it cost to buy 3 large pool equipment s
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6 0
3 years ago
A local police chief claims that 31% of all drug-related arrests are never prosecuted. A sample of 500 arrests shows that 27% of
Elis [28]

Answer:

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X represent the number of arrests that were not prosecuted.

\hat p=0.27 estimated proportion of arrests that were not prosecuted

p_o=0.31 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.31.:  

Null hypothesis:p\geq 0.31  

Alternative hypothesis:p < 0.31  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

3 0
3 years ago
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