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dimulka [17.4K]
3 years ago
7

Simplify 4x+5/6x2-x-12 - 5x/6x2-x-12

Mathematics
2 answers:
MAXImum [283]3 years ago
6 0

Answer:

(5-x)/(3x+4)(2x - 3)

Step-by-step explanation:

Given that:

(4x +5/6x^2 -x-12) - (5x/6x^2-x-12)

As denominator is same so by subtracting the numerators we get:

4x+5 -5x/6x^2-x-12\\5-x/6x^2-x-12

By making factors of the denominator we get:

5-x/6x^2 +8x -9x -12\\5-x/2x(3x +4) -3(3x+4)\\5-x/(3x+4)(2x - 3)

Hence it is the simplified form of given question..

I hope it will help you!

8090 [49]3 years ago
3 0

Simplify 4x+5/6x2-x-12 - 5x/6x2-x-12

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Explanation

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Step 1

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\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

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\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

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