Question

If f(x)=3x^2+2 and g(x)=x^2-9 find (f-g)(x)

Answer 1

Here given, $f(x) = 3x^2+2$ and $g(x) = x^2-9$

we have to find $(f-g)(x)$ which means the subtracting of the functions f(x) and g(x).

$(f-g)(x) = f(x) - g(x)$

= $(3x^2+2) - (x^2-9)$

= $3x^2+2 -x^2-(-9)$

= $3x^2-x^2+2+9$ ( we know that multiplication of negative and negative is positive)

= $2x^2+2+9$

=$2x^2+11$

We have got the required answer here.

$(f-g)(x) = 2x^2+11$

Answer 2

The answer would be 2x²+11.

(f-g)(x)=f(x)-g(x)=3x²+2-(x²-9) = 3x²- x² + 2 --9 = 2x²+2+9 = 2x²+11