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Keith_Richards [23]
3 years ago
12

Complete the isotope symbol with mass numbers of 35

Chemistry
2 answers:
aliya0001 [1]3 years ago
7 0

Explanation:

It is known that isotopes are the species which have same atomic number but different mass number. Whereas a specie which have different atomic number but same mass number are known as isobars.

For example, an element with mass number 35 is chlorine. And, atomic number of a chlorine atom is 17.

This means in a ^{35}_{17}Cl atom there are 17 protons and the number of neutrons will be calculated as follows.

                   Mass number = no. of protons + no. of neutrons

                          35 = 17 + no. of neutrons

                  No. of neutrons = 35 - 17

                                             = 18

Hence, we can conclude that the isotope symbol with mass numbers of 35 is ^{35}_{17}Cl.

amid [387]3 years ago
5 0
The answer would be
35 ============= > A CL = ============> CL 17 === = ======== >Z 
37 CL 17 Isotopes mean A different and equal Z.
Isotopes are atoms that have the same number of protons but a different number of neutrons but still belong to the same element. Though they have the same atomic number but not the same mass number.
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A 21.8 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature ris
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<u>Answer:</u> The heat capacity of calorimeter is 15.66J/^oC

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethanol = 21.8 g

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

\text{Moles of ethanol}=\frac{21.8g}{46.07g/mol}=0.473mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = ?

n = number of moles = 0.473 moles

\Delta H_{rxn} = enthalpy change of the reaction  = -1235 kJ/mol = -1235\times 10^3J/mol     (Conversion factor:  1 kJ = 1000 J)

Putting values in above equation, we get:

-1235\times 10^3J/mol=\frac{q}{0.473mol}\\\\q=(-1235\times 10^3J/mol\times 0.473mol)=-584.16\times 10^3J

To calculate the heat capacity of calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed by the calorimeter = 584.16\times 10^3J

c = heat capacity = ?

\Delta T = change in temperature = T_2-T_1=62.3^oC-25^oC=37.3^oC

Putting values in above equation, we get:

584.16\times 10^3J=c\times 37.3^oC\\\\c=\frac{584.16\times 10^3J}{37.3^oC}=15.66J/^oC

Hence, the heat capacity of calorimeter is 15.66J/^oC

4 0
4 years ago
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