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3 years ago

What are five characteristics of a group on the periodic table?

1 answer:

6 0

1. Group 1 (Alkali Metals)Group 2 (Alkaline Earth Metals)Group 13 (Boron Group)Group 14 (Carbon Group)Group 15 (Nitrogen Group)Group 16 (Chalcogens)Group 17 (Halogens)Group 18 (Noble Gases)
2.The elements in each group have the same number of electrons in the outer orbital
3.Group 2 elements share common characteristics. Each metal is naturally occurring and quite reactive.
4.There are 18 numbered groups in the periodic table
5.many characteristics are common throughout the group

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II. Ionic Equations

mario62 [17]

Answer:

Complete ionic: $\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, {NO_3}^{-} \, (aq) + Ca^{2+}\, (aq) + 2\, Cl^{-}\, (aq) \\ & \rm \to 2\, AgCl\, (s) + Ca^{2+}\, (aq) + 2\, {NO_3}^{-}\, (aq)\end{aligned}$ .

Net ionic: $\begin{aligned}& \rm Ag^{+}\, (aq) + Cl^{-}\, (aq) \to AgCl\, (s)\end{aligned}$ .

Explanation:

Start by identifying species that exist as ions. In general, such species include:

Soluble salts.
Strong acids and strong bases.

All four species in this particular question are salts. However, only three of them are generally soluble in water: $\rm AgNO_3$ , $\rm CaCl_2$ , and $\rm Ca(NO_3)_2$ . These three salts will exist as ions:

Each $\rm AgNO_3\, (aq)$ formula unit will exist as one $\rm Ag^{+}$ ion and one $\rm {NO_3}^{-}$ ion.
Each $\rm CaCl_2$ formula unit will exist as one $\rm Ca^{2+}$ ion and two $\rm Cl^{-}$ ions (note the subscript in the formula $\rm CaCl_2\!$ .)
Each $\rm Ca(NO_3)_2$ formula unit will exist as one $\rm Ca^{2+}$ and two $\rm {NO_3}^{-}$ ions.

On the other hand, $\rm AgCl$ is generally insoluble in water. This salt will not form ions.

Rewrite the original chemical equation to get the corresponding ionic equation. In this question, rewrite $\rm AgNO_3$ , $\rm CaCl_2$ , and $\rm Ca(NO_3)_2$ (three soluble salts) as the corresponding ions.

Pay attention to the coefficient of each species. For example, indeed each $\rm AgNO_3\, (aq)$ formula unit will exist as only one $\rm Ag^{+}$ ion and one $\rm {NO_3}^{-}$ ion. However, because the coefficient of $\rm AgNO_3\, (aq)\!$ in the original equation is two, $\!\rm AgNO_3\, (aq)$ alone should correspond to two $\rm Ag^{+}\!$ ions and two $\rm {NO_3}^{-}\!$ ions.

Do not rewrite the salt $\rm AgCl$ because it is insoluble.

$\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, {NO_3}^{-} \, (aq) + Ca^{2+}\, (aq) + 2\, Cl^{-}\, (aq) \\ & \rm \to 2\, AgCl\, (s) + Ca^{2+}\, (aq) + 2\, {NO_3}^{-}\, (aq)\end{aligned}$ .

Eliminate ions that are present on both sides of this ionic equation. In this question, such ions include one unit of $\rm Ca^{2+}$ and two units of $\rm {NO_3}^{-}$ . Doing so will give:

$\begin{aligned}& \rm 2\, Ag^{+}\, (aq) + 2\, Cl^{-}\, (aq) \to 2\, AgCl\, (s)\end{aligned}$ .

Simplify the coefficients:

$\begin{aligned}& \rm Ag^{+}\, (aq) + Cl^{-}\, (aq) \to AgCl\, (s)\end{aligned}$ .

7 0

2 years ago

Water vapor is condensed steam. True False

adelina 88 [10]

False, because water vapor, water vapour or aqueous vapor, is the gaseous phase of water. It is one state of water within the hydrosphere. Water vapor can be produced from the evaporation or boiling of liquid water or from the sublimation of ice. Unlike other forms of water, water vapor is invisible.

8 0

2 years ago

Consider the following unbalanced redox reaction:

Olegator [25]

Mn04 is being reduced

5 0

3 years ago

A sample of helium gas in a balloon is compressed from 4.0 L to 3.2 L at a constant temperature. If the pressure of the gas in t

vampirchik [111]

Answer:

286 kPa

Explanation:

Boyles law states that volume of gas is inversely proportional to pressure o gas for a fixed amount of gas at constant temperature

P1V1 = P2V2

where P1 is pressure and V1 is volume at first instance

P2 is pressure and V2 is volume at the second instance

substituting the values in the equation

229 kPa x 4.0 L = P2 x 3.2 L

P2 = 286.25 kPa

the new pressure is 286 kPa

4 0

3 years ago

60 POINTS! PLEASE ANSWER!

Mumz [18]

I would have helped but I didn’t understand it sorry that I didn’t answer :(

6 0

2 years ago