The velocity of a 485 kg elevator that has 5900 J of energy is 108.6 m/s
<h3>What is the velocity of the elevator?</h3>
A moving elevator possesses kinetic energy due to its motion.
The velocity of the elevator is calculated from the formula of kinetic energy.
The kinetic energy formula is : Kinetic energy = ¹/₂mv₂
The velocity, v = √2KE/m
v = √(2 * 5900/485)
v = 108.6 m/s
In conclusion, the velocity of the elevator is calculated from the kinetic energy and mass of the elevator.
Learn more about velocity and kinetic energy at: brainly.com/question/25959744
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Answer:
2. A resistor
3. Transistor
Sorry about before, go the answers now!
Answer:
Explanation:
1. Please provide the enthalpy info - I will work on it with the info
2.
i) Reaction a should be modified to match the number of S in equation:
2S + 2O2 -> 2SO2 deltaH = -370kJ
ii) Reaction b should be written reversely to match the reactants of SO2:
2SO2 + O2 -> 2SO3 deltaH = 256kJ
iii) Adding the equations together:
2S + 3O2 -> 2SO3
iv) Enthalpy of the combined reaction = -370+256 = -114kJ
It is negative so the reaction is exothermic.
633.97 L
Explanation:
Well use the combined gas law;
P₁V₁T₁ = P₂V₂T₂
We need to change the temperatures into Kelvin;
18.9°C= 292.05 K
5.9°C = 279.05 K
756 * 512 * 292.05 = 639 * V₂ * 279.05
113,044,377.6 = 178,312.95 V₂
V₂ = 113,044,377.6 / 178,312.95
V₂ = 633.97 L
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