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san4es73 [151]
4 years ago
15

What is the momentum of a 50-kilogram ice skater gliding across the ice at a speed of 5 m/s

Chemistry
1 answer:
chubhunter [2.5K]4 years ago
6 0
Momentum is a term used to quantify the motion of an object has. It is calculated as the the product of the object's mass and the velocity. It is expressed as:
Momentum = m x vMomentum = 50 kg x 5 m/sMomentum = 250 kg m/s
Therefore, the correct answer is the last option.
 
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A process in which one or more substances change to make one or more new substances is called a
svetlana [45]
The answer to your question is: Chemical Reaction.
8 0
3 years ago
Since a parallelogram is defined as a quadrilateral with two pairs of parallel sides, Emily drew in a diagonal of a parallelogra
koban [17]

Explanation:

In the attachment fig ABCD is a parallelogram with AC as diagonal.

we know that,

In  a parallelogram opposite sides are equal and parallel

In a parallelogram sum of adjacent angles is 180°

that is

∠A+∠D= ∠B+∠C= 180°

Also, in  a parallelogram opposite angles are equal.

So in ΔADC and ΔABC

1) AD=BC

2) DC= AB

And

3) ∠ADC= ∠ABC

therefore, ΔADC and ΔABC are congruent to each other and Emily was right.

6 0
3 years ago
You have 0.21 moles of Al how many atoms do you have
ZanzabumX [31]

Number of atoms : 1.26 x 10²³

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

0.21 moles of Al, so n = 0.21

Number of atoms :

\tt N=0.21\times 6.02\times 10^{23}\\\\N=1.26\times 10^{23}

8 0
3 years ago
Did the subscripts (the little numbers<br>​
olga_2 [115]
Hey, you didn’t finish your answer!
Can you finish it so I can help you? Thanks!
4 0
4 years ago
1. Determine the final volume of a 1.5 M HCl solution prepared from 20.0 mL
nadezda [96]

Explanation:

Because molarity is classified as moles of solute per liter of water, dilution of the water may result in a reduction of its concentration.

Therefore, because the amount of moles of solute has to be constant for dilution, you will use the molarity and volume of that same target solution to calculate how many moles of solute will be present in the sample of the stock solution that you dilute.

c  =   \frac{n}{v}

⇒  n = c ⋅  V

n_{HCL} =  0.250 M  ⋅  6.00 L  = 1.5 moles HCl

Now all you have to do is figure out what volume of   6.0 M  stock solution will contain  1.5  moles of hydrochloric acid

c = \frac{n}{v}

V = \frac{n}{c}

V_{Stock} = \frac{1.5 moles}{6.0 \frac{moles}{L} }   = 0.25 L

Expressed in milliliters, the answer will be

V_{Stock} = 250ML →  rounded to two sig figs

7 0
3 years ago
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