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3 years ago

A neutron breaks down to form ?

1 answer:

4 0

A neutron breaks down to form a proton and an electron.
Change in atomic mass when an atom emits gamma radiation. The gamma radiation consists of photons which have no mass so the mass would remain the same.
Re the change in atomic number when an atom emits an alpha particle it loses two protons and two neutrons so the atomic number drops by 2.

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A balloon at 25°C has 30 L. What will the balloon's volume at 35°C?

anygoal [31]

The balloon's volume at 35°C : V₂=31.01 L

<h3>Further explanation</h3>

Given

T₁ = 25°C+273 = 298 K

V₁ = 30 L

T₂ = 35 °C + 273 = 308 K

Required

The new volume (V₂)

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

$\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Input the value :

V₂=(V₁.T₂)/T₁

V₂=(30 x 308)/298

V₂=31.01 L

8 0

2 years ago

In the Bohr model of the atom, an electron in an orbit has a fixed energy level and to move between orbitals what needs to absor

soldier1979 [14.2K]

The answer is heat hope i helped

3 0

3 years ago

If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi

zlopas [31]

Answer:

$T_{eq}=28.9\°C$

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

$Q_{Cd}+Q_{W}=0$

Thus, we insert mass, specific heat and temperatures to obtain:

$m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0$

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

$T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}$

Now, we plug in to obtain:

$T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C$

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

6 0

2 years ago

Which substance can be decomposed by chemical means?

sweet-ann [11.9K]

Are u sure this is the right option? Well, antimony can be decomposed. Including octane.

5 0

3 years ago

Aerobic cellular respiration requires an adequate supply of

Varvara68 [4.7K]

Answer:

oxygen ?

Explanation:

not sure but I think so

3 0

3 years ago