2. A student reacts 6.9 g of lithium chloride and enough copper (I) nitrate. Calculate the mass of precipitate expected.
1 answer:
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Answer:
A) 0.801
Explanation:
The reaction that takes place is:
- 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
First we c<u>alculate the H₂SO₄ moles that reacted</u>:
- 0.355 M * 28.2 mL = 10.011 mmol H₂SO₄
Now we <u>convert H₂SO₄ moles to NaOH moles</u>:
- 10.011 mmol H₂SO₄ *
= 20.022 mmol NaOH
Finally we <u>calculate the molarity of the NaOH solution</u>:
- 20.022 mmol NaOH / 25.0 mL = 0.801 M
So the answer is option A.