<u>We are given:</u><u>_______________________________________________</u>
Volume of Gas (V) = 2.5L
Pressure (P) = 1.2 atm
Temperature (T) = 25°C OR 25+273 = 298 K
Universal Gravitational Constant (R) = 0.0821
<u>Solving for number of moles:</u><u>___________________________________</u>
From the Ideal Gas Equation,
PV = nRT
(1.2)(2.5) = n(0.0821)(298) [plugging the given values]
n = [(1.2)(2.5)] / [0.0821*298]
n = 300 / [298*8.21]
n = 0.12 moles
Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C
Answer:
92.26% of C
Explanation:
To solve this problem we must assume we have 1 mole of benzene. The mole contains 6 moles of C and 6 moles of H. We have to convert these moles to grams in order to find the total mass and mass percent will be:
Mass atom / Total mass * 100
<em>Mass C: </em>6mol C * (12.0107g / mol) = 72.0642g
<em>Mass H: </em>6mol H * (1.00794g / mol) = 6.04764g
<em>total mass: </em>72.0642g + 6.04764g = 78.11184g
Mass percent of C will be:
72.0642g C / 78.11184g* 100
<h3>92.26% of C</h3>
Explanation:
The given reaction is as follows.
Initial : 0.160 0.160 0
Change : -x -x 2x
Equilibrium: 0.160 - x 0.160 - x x
It is given that ![[H_{2}]](https://tex.z-dn.net/?f=%5BH_%7B2%7D%5D)
= [0.160 - x] = 0.036 M
and, ![[I_{2}]](https://tex.z-dn.net/?f=%5BI_%7B2%7D%5D)
= [0.160 - x] = 0.036 M
so, x = (0.160 - 0.036) M
= 0.124 M
As, [HI] = 2x.
So, [HI] = 
= 0.248 M
As it is known that expression for equilibrium constant is as follows.
![K_{eq} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BHI%5D%5E%7B2%7D%7D%7B%5BH_%7B2%7D%5D%5BI_%7B2%7D%5D%7D)
= 
= 47.46
Thus, we can conclude that the equilibrium constant, Kc, for the given reaction is 47.46.
Answer:
1.146 x 10⁴ year.
Explanation:
- The decay of carbon-14 is a first order reaction.
- The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
- The integration law of a first order reaction is:
<em>kt = ln [A₀]/[A]</em>
<em></em>
k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.
t is the time = ??? years.
[A₀] is the initial percentage of carbon-14 = 100.0 %.
[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.
∵ kt = ln [Ao]/[A]
∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]
(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.
∴ <em>t </em>= 1.386/
(1.21 x 10⁻⁴ year⁻¹) = <em>1.146 x 10⁴ year.</em>
The reaction of hydrochloric acid and sodium hydroxide is a neutralization reaction wherein a mixture of acid and base produces salt, water, and energy in the form of heat. A neutralization reaction is exothermic, thus producing heat. This is why the beaker felt warm to the touch.
