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mylen [45]
2 years ago
10

Find the length of the line joining the following points. 1. P(-4,3) and Q (5,16) ​

Mathematics
2 answers:
jekas [21]2 years ago
6 0
I have this same problem I need help too!!!
Verdich [7]2 years ago
4 0

Answer:

Applying the formula for the distance between two points

(-4,3) and (5,16)

x₁=-4 y₁=3

x₂= 5 y₂=16

d = √(y₂-y₁)²+(x₂-x₁)²

d= √(16-3)² + (5-4)²

d=√170

d=13.04units.

The distance between these points give the length of the line connecting them.

Hope this helps!

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on a certain hot Summer's Day 613 people use the public swimming pool the daily prices are $1.75 for children $2.25 for adults t
Elodia [21]

389 children and 224 adults were at the pool that day.

Step-by-step explanation:

Cost of one child ticket = $1.75

Cost of one adult ticket = $2.25

Total people = 613

Total receipts worth = $1184.75

Let,

Number of children = x

Number of adults = y

According to given statement;

x+y=613    Eqn 1

1.75x+2.25y=1184.75    Eqn 2

Multiplying Eqn 1 by 1.75

1.75(x+y=613)\\1.75x+1.75y=1072.75\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(1.75x+2.25y)-(1.75x+1.75y)=1184.75-1072.75\\1.75x+2.25y-1.75x-1.75y=112.00\\0.50y=112.00

Dividing both sides by 0.50

\frac{0.50y}{0.50}=\frac{112.00}{0.50}\\y=224

Putting y=224 in Eqn 1

x+224=613\\x=613-224\\x=389\\

389 children and 224 adults were at the pool that day.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/11236033
  • brainly.com/question/11306893

#LearnwithBrainly

6 0
3 years ago
A car dealership decreased the price of a certain car by 13%. The original price was $45,400.
ira [324]

Answer:

5902

Step-by-step explanation:

Solution: 13% off 45400 is equal to (13 x 13) / 100 = 5902.

5 0
3 years ago
Which transformations could have occurred to map ABC
antoniya [11.8K]
A translation and dilation
5 0
3 years ago
Please help! The selected one is wrong
kirill [66]
Plug g(x) in for every x in f(x) then substitute 4, you’ll get (f o g)(4) = 34
8 0
3 years ago
Consider a rabbit population​ P(t) satisfying the logistic equation StartFraction dP Over dt EndFraction equals aP minus bP squa
maria [59]

Solution:

Given :

$\frac{dP}{dt}= aP-bP^2$         .............(1)

where, B = aP = birth rate

            D = $bP^2$  =  death rate

Now initial population at t = 0, we have

$P_0$ = 220 ,  $B_0$ = 9 ,  $D_0$ = 15

Now equation (1) can be written as :

$ \frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$    .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$    and     $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

          = $\frac{9 \times 220}{15}$

          = 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

        = $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$ 220-88e^{\frac{-99}{2420} t}=200$

$ e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0
3 years ago
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