The parent, solid line function is y = log(x), and the dashed line function has been translated five units upwards. That means that the answer must be y = log(x) + 5
Answer:
I got x<equal to -11 or x>equal to4
Step-by-step explanation:
x^2+15x+44=0
(x+4)(x+11)=0(Factor left side of equation)
x+4=0 or x+11=0(Set factors equal to 0)
x=−4 or x=−11
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<−11(Works in original inequality)
−11<x<−4(Doesn't work in original inequality)
x>−4(Works in original inequality)
Answer:
x<−11 or x>−4
Given:
Principal = Rs. 6000
Rate of simple interest = 6% per annum.
Time = 4 years
To find:
The simple interest and amount.
Solution:
Formula for simple interest:

Where, P is principal, r is the rate of interest and t is the number of years.
Putting P=6000, r=6 and t=4, we get



Now,



Therefore, the simple interest is Rs. 7440 and the amount is Rs 7440.
Assuming R and H:
So volume is pir^2 * H = 1500 and H = 1500/(pir^2) while surface area is A= 2pir*H + 2pir^2
A = 2pir(r+h)= 2piR^2 + 2pir*1500/(pir^2)= 2piR^2 + 3000/r
For A to take minimum, get the derivative 4pir - 3000/R^2 and let it be 0
4pir^3 - 3000 = 0
r = cbrt(3000/(4pi)) ≈ 6.20
h = 1500/(pi(6.20)^2) ≈ 12.42