Answer:D
Explanation:
Given
Force required to move a box at steady rate is F=78 N
Weight of Block W=150 N
If the block is moving at a steady rate then net Force acting on it is zero
Applied Force must balance the Friction force
where N=normal Reaction
Normal reaction must be equal to weight
Answer:
By Gauss' Law the sphere will appear externally as if all of the charge were concentrated at the center of the sphere.
E = K Q / r^2 = K Q / .528^2
Q = 1710 * .528^2 / 9.00E9 Coulombs
Q = 5.30E-8 Coulombs on sphere
V = 4/3 π R^3 = 4/3 π * .384^3 = .237 m^3
ρ = Q / V = 5.30E-8 / .237 = 2.23E-7 C/m^3
At .223 from center Q = 4/3 π .223^3 * ρ (charge outside this radius will not affect electric field outside .223 m)
Q = 2.23E-7 * 4/3 * π * .223^3 = 1.04E-8 Coulombs
E = 9.00E9 * 1.04E-8 / .223^2 = 1880 N/C
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