1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mrrafil [7]
3 years ago
8

Which energy source is formed when organic matter is trapped underground without exposure to air or moisture?. . A. natural gas.

B. coal. C. oil. D. biomass fuels
Physics
1 answer:
nikklg [1K]3 years ago
8 0

Answer:

The correct answer is option B. coal

Explanation:

Coal is made of remains of organic material including trees and other vegetation which got trapped beneath the earth’s surface or at the bottom of the swamps. After burial below the ground the organic material was acted upon by the high temperature and pressure in the absence of air to form peat. Peat after further processing for a longer period of time converted into coal

You might be interested in
What do you know about muscular fitness activities?
Ulleksa [173]

Answer:

Examples of muscle-strengthening activities include:

lifting weights.

working with resistance bands.

heavy gardening, such as digging and shovelling.

climbing stairs.

hill walking.

cycling.

dance.

push-ups, sit-ups and squats.

Explanation:

3 0
3 years ago
2. El sonido de una ballena es en especial de frecuencia baja, pero existe una especie de ballena la Whalien cuya frecuencia es
ikadub [295]

Answer:

The sound of a whale is especially low frequency, but there is a species of whale the Whalien whose frequency is 52 Hz, if the propagation speed of the wave is 1400m / s What will be its period in the water and the air? And what will be the wavelength in each medium? Remember that the propagation speed in air is 340m / s

Explanation:

From wave equation, the speed, wavelength and frequency is related using

V = fλ

Where

V is the speed

f is the frequency

And λ is the wavelength

So,

The frequency of the whale is

f = 52Hz

The speed in water is V_w = 1400m/s

The speed in air is V_a = 340m/s

We want to find the period in each medium, the period is related to the frequency and since the frequency is constant.

Then, period in equal in both medium

T = 1 / f

T_w = T_a = 1 / f

T = 1 / 52

T = 0.0192 seconds

We want to find the wavelength in each medium

For water,

V = fλ

V_w = f × λ_w

Then,

λ_w = V_w / f.

λ_w = 1400 / 52 = 26.92 m

The wavelength in water is 26.92m

Now, in air

V = fλ

V_a = f × λ_a

Then,

λ_a = V_a / f.

λ_a = 340 / 52 = 6.54 m

The wavelength in air is 6.54 m

In Spanish

De la ecuación de onda, la velocidad, la longitud de onda y la frecuencia se relacionan usando

V = fλ

Dónde

V es la velocidad

f es la frecuencia

Y λ es la longitud de onda

Entonces,

La frecuencia de la ballena es

f = 52Hz

La velocidad en el agua es V_w = 1400m / s

La velocidad en el aire es V_a = 340m / s

Queremos encontrar el período en cada medio, el período está relacionado con la frecuencia y dado que la frecuencia es constante.

Luego, período igual en ambos medios

T = 1 / f

T_w = T_a = 1 / f

T = 1/52

T = 0.0192 segundos

Queremos encontrar la longitud de onda en cada medio

Para agua,

V = fλ

V_w = f × λ_w

Entonces,

λ_w = V_w / f.

λ_w = 1400/52 = 26,92 m

La longitud de onda en el agua es de 26,92 m.

Ahora en el aire

V = fλ

V_a = f × λ_a

Entonces,

λ_a = V_a / f.

λ_a = 340/52 = 6,54 m

La longitud de onda en el aire es de 6.54 m.

8 0
4 years ago
Ask Your Teacher The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s
adell [148]

Answer:

\theta = 20\ rev

Explanation:

Case 1

Given,

initial angular speed = 0 rev/s

final angular speed = 2 rev/s

time, t = 7 s

angular acceleration of the washer

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{2-0}{7}

\alpha = 0.286\ rev/s^2

using equation of rotational motion

\omega_f^2 = \omega_i^2 + 2 \alpha \theta_1

2^2 = 0^2 + 2\times 0.286 \times \theta_1

\theta_1 = 7 rev

Case 2

Given,

initial angular speed = 2 rev/s

final angular speed = 0 rev/s

time, t = 12 s

angular acceleration of the washer

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{0-2}{13}

\alpha = -0.154\ rev/s^2

using equation of rotational motion

\omega_f^2 = \omega_i^2 + 2 \alpha \theta_2

0^2 = 2^2 + 2\times (-0.154) \times \theta_2

\theta_2 = 13 rev

total revolution in this case

\theta = \theta_1 + \theta_2

\theta =7 +13

\theta = 20\ rev

total revolution of the washer is equal to 20 rev.

6 0
3 years ago
A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m
Degger [83]

Answer:

a)t  = 1,43 s

b) V = 10,49 m/s

c) V₀ₓ = 10,49 m/s   ;    V₀y = 14,01 m/s

d) Vf = 17,5 m/s

Explanation:

According to the problem statement

V₀ = V₀ₓ    and  V₀y = 0

And at the end of the movement t = ?  the distance y = 10 m

Therefore as

h = V₀y - (1/2)*g*t²

Vertical distance y = h = 10 = V₀y*t - 0,5 (-9,8)*t²

10 = 4,9*t²

t² = 10/4,9    ⇒  t² = 2,04 s

t  = 1,43 s

a) 1,43 s is the time of movement

b) V₀ = V₀ₓ        V₀y = 0     and  V₀ₓ = Vₓ     ( constant )

Just before touching the ground, the horizontal distance is

hd = 15 = Vₓ * t

Then  15 /1,43 = Vₓ = V₀ₓ

Vₓ = 10,49 m/s

Then initial speed is V = 10,49 m/s    since V₀y = 0

Vf² = Vₓ² + Vy²

Vyf = V₀y - g*t

Vyf =  0 - 9,8 *1,43

Vyf = - 14,01 m/s

And finally the speed when the projectile strike the ground is:

Vf² = Vₓ² + Vy²

Vf = √ (10,49)² + (14,01)²

Vf = 17,50 m/s

3 0
3 years ago
A tiger leaps horizontally out of a tree that is 3.70 m high. If she lands 4.80 m from the base of the tree, calculate her initi
Levart [38]

Answer:

Explanation:

Given that

Height of the tree is 3.7m

Therefore yo=3.7m

yox= 0m

The tiger lands 4.8m from the tree

Then, Range x=4.8m

Since she flies horizontally and she lands away from the bottom of the tree, her path will be trajectory as shown in the attachment

Let know the time of flight, using the equation of motion

voy is the initial velocity of the vertical motion of the is the tiger, which is zero at the beginning.

y = y0 + voy*t + ½*g*t²

Given that,

y=3.7m

yo=0m

voy=0m/s

g=9.81m/s²

y = y0 + voy*t + ½*g*t²

3.7=0+0•t+½×9.81×t²

3.7=0+0+4.905t²

3.7=4.905t²

t²=3.7/4.905

t²=0.7543

t=√0.7543

t=0.87sec

Time to reach the ground is

Now to know the initial velocity of the horizontal motion, using equation of motion

x=xo+Voxt

Vox is the horizontal initial velocity of the tiger.

x=xo+Voxt

4.8=0+Vox×0.87

4.8=0+0.87Vox.

4.8=0.87Vox.

Then, Vox=4.8/0.87

Vox=5.52m/s

Then, her initial velocity Vo

Vo=√voy²+vox²

Vo=√0²+5.52²

Vo=√5.52²

Vo=5.52m/s

The initial velocity is 5.52m/s

5 0
4 years ago
Other questions:
  • How is coulomb's law similar to newton's law of gravity?
    15·1 answer
  • An airplane accelerat s down a runway at 3.20 m/s(squared) for 32.8s until is finally lifts off the ground. Presume to he plane
    6·1 answer
  • which has a greater kinetic energy a 20.0kg greyhound running at 16m/s or a 923.0kg polar bear running at 2.5m/s
    8·1 answer
  • Two blocks are sliding along a frictionless track. Block A (mass 4.03 kg) is moving to the right at 3.00 m/s. Block B (mass 4.84
    5·1 answer
  • Rifle and Bullet A rifle is aimed horizontally at a target 33 m away. The bullet hits the target 1.3 cm below the aiming point.
    7·1 answer
  • Can rock undergo compression, tension, and shear stress all at once?<br> explain
    13·1 answer
  • Which scientist explained why binary stars change colors?
    7·1 answer
  • A converging lens is used to focus light from a small bulb onto a book. The lens has a focal length of 10.0 cm and is located 40
    5·1 answer
  • A ball falling from a building has a kinetic energy of 2000 J and potential energy of 2376 J. What is the mechanical energy of t
    11·1 answer
  • Please help, im stuck on this question
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!