Answer:
y (lambda) = c / f incident wavelength
y = 3 * E8 / 2.4 * E9 = .125 m incident wavelength
y' = .125 / 1.45 = .0862 m wavelength inside of tray
T = y' / 4 thickness required for phase change at bottom
T = .0862 m / 4 = .0261 m = 2.61 cm
<span>16.82 x 0.04 = 0.67 rad
I hope I helped if you really need I can explain to you how I got that answer but Thats correct im sorry it took 2 days for me to find this answer but if you or anybody else still needs the answer for this question here it is :) have a fantastic day guys Spring Break is coming up soon :)</span>
Answer:
the magnetic field experienced by the electron is 0.0511 T
Explanation:
Given the data in the question;
Wavelength λ = 21 cm = 0.21 m
we know that Bohr magneton μ
is 9.27 × 10⁻²⁴ J/T
Plank's constant h is 6.626 × 10⁻³⁴ J.s
speed of light c = 3 × 10⁸ m/s
protein spin causes magnetic field in hydrogen atom.
so
Initial potential energy = -μ
B × cos0°
= -μ
B × 1
= -μ
B
Final potential energy = -μ
B × cos180°
= -μ
B × -1
= μ
B
so change in energy will be;
ΔE = μ
B - ( -μ
B )
ΔE = 2μ
B
now, difference in energy levels will be;
ΔE = hc/λ
2μ
B = hc/λ
2μ
Bλ = hc
B = hc / 2μ
λ
so we substitute
B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)] / [2(9.27 × 10⁻²⁴) × 0.21 ]
B = [ 1.9878 × 10⁻²⁵ ] / [ 3.8934 × 10⁻²⁴ ]
B = 510556326.09
B = 0.0511 T
Therefore, the magnetic field experienced by the electron is 0.0511 T
Answer:
0.0247212 Joules
-0.0247212 Joules
Explanation:
Potential energy
![PE=mgh\\\Rightarrow PE=2.52\times 10^{-5}\times 9.81\times 100\\\Rightarrow PE=0.0247212\ Joules](https://tex.z-dn.net/?f=PE%3Dmgh%5C%5C%5CRightarrow%20PE%3D2.52%5Ctimes%2010%5E%7B-5%7D%5Ctimes%209.81%5Ctimes%20100%5C%5C%5CRightarrow%20PE%3D0.0247212%5C%20Joules)
a) The work done by the gravitational force is given by the potential energy that the body has at the start of the fall.
Work done is considered as positive if the force which is being applied is in the direction of motion.
Hence, the work done on the raindrop by the gravitational force is 0.0247212 Joules
b) As the drop is falling the air resistance provides an opposite force this means the sign of the work done will be negative.
So, the work done on the raindrop by air resistance is -0.0247212 Joules