Answer:
X = 15.88 m
Explanation:
Given:
Initial Velocity V₀ = 13.4 m/s
θ = 30.1 °
g = 9.8 m/s²
To Find horizontal distance let "X" we have to time t first.
so from motion 2nd equation at Height h = 0
h = V₀y t + 1/2 (-g) t ² (ay = -g)
0 = 13.4 sin 30.1° t - 0.5 x 9.81 x t² (V₀y = V₀ Sin θ)
⇒ t = 1.37 s
Now For Horizontal distance X, ax =0m/s²
X = V₀x t + 1/2 (ax) t ²
X = 13.4 m × cos 30.1° x 1.37 s + 0
X = 15.88 m
Answer:
Average speed: approximately 
.
Average velocity: approximately 
(to the north.)
Explanation:
Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.
In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.
In this question, the path George took required him to travel 
in total. Hence, the distance George travelled would be 
. However, since George stopped at a point 
to the north of where he started, his displacement would be only 
to the north.
Divide total distance by total time to find the average speed.
Divide total displacement by total time to find average velocity.
The total time of travel in this question is 
.. Therefore:
.
.
Answer: 3.27kg
Explanation:
Inertia can be said to be the resistance of an object to a change in its motion. This includes a change in its direction. An object will stay still or keep moving at the same speed and in a straight line, except it is acted upon by an unbalanced external force.
Given F = 30N
r = 0.14m
a = 130rad/s²
Then, T = Fr
T = 30*0.14
T = 4.2Nm
Also, T = inertia * acceleration
Inertia = 4.2/a
Inertia = 4.2/130
Inertia = 0.032
Also, inertia = mr²/2
0.032 = m * (0.14²)/2
0.032 = m * 0.0098
m = 0.032/0.0098
m = 3.27kg
The answers to all three questions depend on WHICH branch
of Physics you're talking about . . . a piece of information you've
neglected to specify.
Elizabeth, weight formula is 624 divided by 9.8 which is greater than 57kg
