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3 years ago

Given trapezoid ABCD, what is the length of ?

Mathematics

1 answer:

hichkok12 [17]3 years ago

3 0

Answer:

XY = 18 units.

Step-by-step explanation:

The sum of the top and bottom lines = 2 * middle line, so:

6x + 1 + s = 2(4s - 2)

7s + 1 = 8s - 4

5 = s.

So XY = 4(5) - 2 = 18.

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Manuela is having mugs made for a fundraiser. The Cup Company will make them for $4 each plus a $30 set-up charge. Mugs Are Us w

amm1812

Answer:

The price will be the same for both companies at 60 mugs

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

m is the rate of change

b is the fixed amount

Assume that the number of mugs is x and the total cost of them is $y

∵ The Cup Company will make them for $4 each plus a $30

set-up charge

∴ The cost per mug = $4

∴ m = 4

∴ The fixed amount = $30

∴ b = 30

∵ x is the number of mugs

∵ y is the cost of them

→ Substitute the values of m and b in the form of the equation

∴ y = 4x + 30 ⇒ (1)

∵ Mugs Are Us will make them for $4.50 each with no set-up charge

∴ The cost per mug = $4.50

∴ m = 4.5

∴ The fixed amount = 0

∴ b = 0

∵ x is the number of mugs

∵ y is the cost of them

→ Substitute the values of m and b in the form of the equation

∴ y = 4.5x + 0

∴ y= 4.5x ⇒ (2)

∵ The price be the same for both companies

→ Equate the right sides of (1) and (2)

∴ 4.5x = 4x + 30

→ Subtract 4x from both sides

∵ 4.5x - 4x = 4x - 4x + 30

∴ 0.5x = 30

→ Divide both sides by 0.5

∴ x = 60

∴ The price will be the same for both companies at 60 mugs

4 0

3 years ago

Which of the following correctly expresses sin (70) + sin(30) as a product?

JulsSmile [24]

Answer:

2sin50 cos20

Step-by-step explanation:

We need to write sin (70) + sin(30) as a product. The formula used here is :

$\sin A+\sin B=2\sin (\dfrac{A+B}{2})\cos(\dfrac{a-b}{2})$

Here, A = 70 and B = 30

So,

$\sin 70+\sin 30=2\sin (\dfrac{70+30}{2})\cos(\dfrac{70-30}{2})\\\\\sin 70+\sin 30=2\sin 50\cos20$

So, the value of sin (70) + sin(30) is 2sin50 cos20. Hence, the correct option is (c).

7 0

4 years ago

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom

gtnhenbr [62]

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x + 8

Expand the equation

x^2 + 6x + 8 = x^2 + 4x + 2x + 8

Factorize the equation

x^2 + 6x + 8 = (x + 2)(x + 4)

Hence, the signs in the binomials should be both positive