sinR = 
noting that the sin ratio = 
opposite to ∠P is QR and hypotenuse is PQ ( opposite right angle )
Answer/Step-by-step explanation:
The equation of the line that passes through the two points would be correct if each point, when substituted into the equation, satisfy the equation.
This is what I mean:
Given the equation of the line, y = 2x - 5, and the two points (-2, -9) and (3, 1):
For the first point, substitute x = -2, and y = -9 into y = 2x - 5.
Thus:
-9 = 2(-2) - 5
-9 = -4 - 5
-9 = -9 (this is true). It means the line runs through the point (-2, -9)
For the second point, substitute x = 3, and y = 1 into y = 2x - 5
This:
1 = 2(3) - 5
1 = 6 - 5
1 = 1 (this is true). This also means the point, (3, 1) is also a point that the equation runs across.
<h3>Answer:</h3>
One line segment is 10 cm and the other one is 45 cm
Hope this helps you!
Have an amazing day :)
<h3 />
The answer is
<span>C) Samara’s sample is random because she asks the first 10 people she sees.
</span>
<h3>Corresponding angles =
angle 1 and angle 5</h3>
They are on the same side of the transversal cut (both to the left of the transversal) and they are both above the two black lines. It might help to make those two black lines to be parallel, though this is optional.
Other pairs of corresponding angles could be:
- angle 2 and angle 6
- angle 3 and angle 7
- angle 4 and angle 8
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<h3>Alternate interior angles = angle 3 and angle 5</h3>
They are between the black lines, so they are interior angles. They are on alternate sides of the blue transversal, making them alternate interior angles.
The other pair of alternate interior angles is angle 4 and angle 6.
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<h3>Alternate exterior angles = angle 1 and angle 7</h3>
Similar to alternate interior angles, but now we're outside the black lines. The other pair of alternate exterior angles is angle 2 and angle 8
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<h3>Same-side interior angles = angle 3 and angle 6</h3>
The other pair of same-side interior angles is angle 4 and angle 5. They are interior angles, and they are on the same side of the transversal.
