3 years ago

Which expression is equivalent to OA2 42 O -7 1

Mathematics

1 answer:

Marina CMI [18]3 years ago

8 0

it is the last one before the time

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15 PTS! ILL GIVE BRAINLIEST!

CaHeK987 [17]

Your answer is c. As you multiply 1/2 by both of the factors inside the parentheses you’ll find that 1/2(b-30)=1/2b-15

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3 years ago

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If x- 3/4 =2 1/9 what does the x equals?

Romashka-Z-Leto [24]

3/4+-2 1/9=your ****ing answer

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3 years ago

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

3 0

2 years ago

Help please i will give brainliest

tangare [24]

Answer:

7 $\geq$ r

Step-by-step explanation:

-1.3 $\geq$ 2.9-0.6r

-2.9 -2.9

-4.2 ≥ -0.6r

/-0.6 /-0.6

7 ≥ r

8 0

3 years ago

R/5 - 6 = -1 r=1 r=5 r=10 r=25

posledela

R = 30 because r = 1,5,10,25
30/5+1=7
6+1=7

5 0

3 years ago