(2+y)^3?
= ((2+y)x(2+y))x(2+y)
= (4+4y+y2) x (2+y)
= 8 + 8y + 2y2 + 4y + 4y2 + y3
= y3 + 6y2 + 12y + 8
The first one is your answer, hope this helped!
Answer:
help pls
Step-by-step explanation:
plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz.
pls...
The answer is c pls mark me as brainless
Answer:
Abundance of isotope 79Br=51% and abundance of 81Br=49%
Step-by-step explanation:
We are given that
Mass of 79Br=78.9183 u
Mass of 81Br=80.9163 u
Average atomic mass of bromine=79.90 u
We have to find the relative abundance of the two bromine isotopes.
Let x be the abundance of 79Br
Then , abundance of 81Br isotopes=1-x
Average atomic mass=Mass of isotope(abundance of isotope)+Mass of other isotope(abundance of other isotope)
Using the formula
Percentage of isotope with abundance 0.51=%
Abundance of other isotope=1-0.51=0.49
Percentage of other isotope with abundance 0.49=%
Answer:
I DESERVE BRAINLIEST
Step-by-step explanation:
C=5.5*2*PI
C=11*pi
C=34.5575191895
C= 34.56
A=pi*5.5^2
A=30.25*Pi
A= 95.0331777711
A= 95.03