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FinnZ [79.3K]
3 years ago
10

For the following exercise, determine the range (possible values) of the random variable, X. A batch of 300 machined parts conta

ins 10 that do not conform to customer requirements. The random variable is the number of parts in a sample of 5 parts that do not conform to customer requirements. Choose the correct answer.
a. The range of X is {0,1,2,3,4,5,6}
b. The range of X is {0,1,2,3,4,5,6}
c. The range of X is {0,1,2,3,4,5,6}
d. The range of X is {0,1,2,3,4,5,6}
e. The range of X is {0,1,2,3,4,5,6}
Mathematics
1 answer:
solmaris [256]3 years ago
5 0

Answer:

{0,1,2,3,4,5}

Step-by-step explanation:

We are given that

Total number of  machine parts=300

Number of defective machine parts=10

Total number of good machine parts=300-10=290

Sample contain parts that do not conform to customer requirement=5

X  is a random variable which is the number of parts in a sample of 5 parts that do not conform to customer requirements.

We have to find the correct answer.

The sample contain 5 parts

Therefore, the possible values of random variable X

0,1,2,3,4,5

Hence, the range of X is given by

{0,1,2,3,4,5}

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never [62]

A regular octagon has all its eight sides congruent. The line segments joining each of the vertices of a regular octagon to its center are called the radii of the octagon. These 8 radii divide a regular octagon into 8 congruent isosceles triangles. Area of each isosceles triangle is

A_{triangle}=\dfrac{1}{2}a^2\sin \alpha,

where a is length of the side of the octagon and \alpha is the angle between two radii of the octagon.

In regular octagon

\alpha=\dfrac{360^{\circ}}{8}=45^{\circ}.

Then the area of regular octagon is

A_{octagon}=8A_{triangle}=8\cdot \dfrac{1}{2}a^2\sin \alpha=4\cdot (6)^2\cdot \sin 45^{\circ}=4\cdot 36\cdot \dfrac{\sqrt{2}}{2}=72\sqrt{2} sq. m.

Answer: A_{octagon}=72\sqrt{2} sq. m.


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4 years ago
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Rama09 [41]
A= 3
b= 4

=3.14(a^2 + ab)
substitute the given a & b values in expression

=3.14((3)^2 + (3*4))
multiply inside parentheses

=3.14(9 + 12)
add inside parentheses

=3.14(21)
multiply

=65.94


ANSWER: 65.94

Hope this helps! :)
4 0
4 years ago
— 7х – 10 = 18 + 3x<br> Solve the equation
chubhunter [2.5K]

Answer:

-2.8 = x

Step-by-step explanation:

-7х – 10 = 18 + 3x

+7x. +7x

-10. = 18+ 10x

-18. -18

-28. = 10x

/10. /10

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3 years ago
Solve for kkk. \dfrac{k}4+ 3= 14 4 k ​ +3=14
masha68 [24]

Answer: k=1

Step-by-step explanation:

Simplify   1/k

    3     2         1

 (((—+2)-(—•k))-4)-(—-2)  = 0

    k     k         k

2.1   Subtracting a whole from a fraction

      2     2 • k

   2 =  —  =  —————

        1       k  

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

1 - (2 • k)     1 - 2k

———————————  =  ——————

     k            k  

Simplify  2/k

 3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

Simplify 3/k

  3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

5.1   Adding a whole to a fraction

 3                      (1 - 2k)

 (((— +  2) -  2) -  4) -  ————————  = 0

    k                         k    

6.1   Subtracting a whole from a fraction

        2     2 • k

   2 =  —  =  —————

        1       k  

7.1   Subtracting a whole from a fraction

3 + 2 • k     2k + 3

—————————  =  ——————

    k           k  

8.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

        2     2 • k

   2 =  —  =  —————

        1       k  

9.1     Pull out like factors :

  2 - 2k  =   -2 • (k - 1)

10.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -2•(k-1)

 ———————— • k = 0 • k

    k    

Now, on the left hand side, the  k  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

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Equations which are never true:

10.2      Solve :    -2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

10.3      Solve  :    k-1 = 0

Add  1  to both sides of the equation :

                     k = 1

5 0
3 years ago
A container holds 5L of fluid. Does it hold more than or less than 500mL of fluid
Yuri [45]

There are 1000 mL in one liter, so there are 5000 Ml in the 5 L container. thus, it holds more than the 500 mL container. 
7 0
4 years ago
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