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igomit [66]
3 years ago
14

Given: are diameters m∠3 = A) 39 B) 78 C) 102

Mathematics
2 answers:
Blizzard [7]3 years ago
8 0
I just did this a few seconds ago and the correct answer is 78. The check above the number is green which means its correct. 
ratelena [41]3 years ago
5 0

Answer:

78 is wrong ,its 39

Step-by-step explanation:

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What slope is parallel to:<br> m = 4
andreyandreev [35.5K]

Answer:

m = 4

Step-by-step explanation:

Parallel means to have the same slope but different x- and y- intercepts

An example would be y = 4x + 6 and y = 4x - 2

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Sanjeev had 350 marbles and he gave 1/5 of them to his friend, Rayson. How many
kicyunya [14]

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70

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A construction crew is lengthening a road. The road started with a length of 57 miles, and the crew is adding 4 miles to the roa
Alexus [3.1K]
The equation you can use to relate L to D uses the information in the first part of the problem. First, if we just add 4 miles every day (ignoring the other piece), the length of the road would be 4 times the number of days, or L = 4D. But since we started with 57 miles built, we have to add that in order to get the total length, so the equation would be:

L = 4D + 57

You can use this question to find any value of L or D if you know one of them. According to the questoin, we know the crew worked 34 days (or D). So if you plug in 34 for D you'll get:

L = 4(34) + 57 ->
L = 136 + 57 ->
L = 193
6 0
3 years ago
What is the total area, in square inches, of the shaded sections of the trapezoid below?
Rudik [331]
You can add 5.6 and 5.9 which is 11.5 x 8 = 92 then divide that by 2 and you have 46
6 0
3 years ago
Find f(g(x)). State the domain of the composite function.<br> f(x) = 3x-2/x+1<br> g(x) = x+5/2x-3
AnnyKZ [126]

Answer:

ℝ - {(-2/3),(3/2)}

Step-by-step explanation:

We want the domain of f(g(x)). So, firstly, we have to find the domain for g(x) and, then, for f(g(x)).

- Domain of g(x): Since the expression is a fracion, we must exclude the values of x that make null the denominator. Hence,

g(x)=\dfrac{x+5}{2x-3}\Longrightarrow 2x-3\neq 0\iff \boxed{x\neq\dfrac{3}{2}}

- Domain of f(g(x)): We'll find its expression:

f(x) = \dfrac{3x-2}{x+1}\\\\f(g(x)) = \dfrac{3g(x)-2}{g(x)+1}\\\\f(g(x)) = \dfrac{3\cdot\dfrac{x+5}{2x-3}-2}{\dfrac{x+5}{2x-3}+1}=\dfrac{~~~\dfrac{3(x+5)-2(2x-3)}{2x-3}~~~}{\dfrac{(x+5)+(2x-3)}{2x-3}}\\\\f(g(x)) =\dfrac{3(x+5)-2(2x-3)}{(x+5)+(2x-3)}=\dfrac{3x+15-4x+6}{x+5+2x-3}\\\\\boxed{f(g(x)) =\dfrac{21-x}{3x+2}}

Now, once again, we have to exclude the values of x that make the denominator equals to zero. Thus,

f(g(x)) =\dfrac{21-x}{3x+2}\Longrightarrow 3x+2\neq0\iff \boxed{x\neq-\dfrac{2}{3}}

Lastly, we may write the domanin of f(g(x)):

D(f(g(x)) = \left]-\infty,-\dfrac{2}{3}\right[\cup\left]-\dfrac{2}{3},\dfrac{3}{2}\right[\cup\left]\dfrac{3}{2},\infty\right[

or, just writing in a shorter way:

\boxed{D(f(g(x)) = \mathbb{R}-\left\{-\dfrac{2}{3},\dfrac{3}{2}\right\}}

7 0
2 years ago
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