Answer:
<a = 90° (180-90 supplementary angle)
<b = 90° (180-90 supplementary angle)
<d = 48° (180-132 supplementary angle)
<e = 132° (opposite angle)
<c = 42° (interior angles of a triangle equal 180. 180-48-90=42)
Step-by-step explanation:
<a = 90° (180-90 supplementary angle)
<b = 90° (180-90 supplementary angle)
<d = 48° (180-132 supplementary angle)
<e = 132° (opposite angle)
<c = 42° (interior angles of a triangle equal 180. 180-48-90=42)
B
The range of the parent linear function is All Real Numbers which includes negative numbers
Answer:
Speed = Distance ÷ Time
time = distance ÷ speed
Step-by-step explanation:
248 ÷ 55 * 60 = 270.54 minutes
First simplify this inequality:
Now you can graph this inequality. Draw the vertical dashed line x=3 and shade the region to the right from this line. This is exactly the region that represents the solution of inequality (see attached diagram for details).
Based on the information of the table, you have:
1. The ratio is 105/150. By simplifying you get for the ratio 7/10.
2. The students that prefer action movies are 75+90 = 165 and the total numbe of students is 180+240 = 420. Then, the fraction of students who prefer action movies is:
165/420 = 11/28
3. The fraction of seventh graders students that prefer action movies is:
75/180 = 5/12
4. The percent of student that prefer comedy is:
105 + 150 = 255 total student that prefer comedy
420 total number of students
the fraction is:
(x/100)420 = 255
solve for x:
x = 255(100/420)
x = 60.71
the percent of students is 60.71%
5. The percent of eighth graders student who prefer action moveis is:
(x/100)240 = 90
x = 90(100/240)
x = 37.5
the percent of students is 37.5%
6. To determine which from the given grades has the greatest percent of student that prefer action movies, calculate the percent of student in seventh-grade:
(x/100)180 = 75
x = 75(100/180)
x = 41.66
the percent of student is 41.66%
then, seventh grade has the greatest percent of student that prefer action movies.
