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fomenos
3 years ago
15

A 5.00 l sample of a gas exerts a pressure of 1040 torr at 50.0°c. In what volume would the same sample exert a pressure of 1.00

atm at 50.0°c?
Chemistry
1 answer:
Karolina [17]3 years ago
8 0

Answer: 7L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.  

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=1040torr=1.4atm(1torr=0.0013atm)\\V_1=5.00L\\P_2=1atm\\V_2=?

Putting values in above equation, we get:

1.4\times 5.0L=1atm\times V_2\\\\V_2=7L

The volume would be 7L at pressure of 1.00 atm at 50.0°C.

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<h3>1.</h3>

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

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<h3>2.</h3>

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Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be \rm cm \cdot cm, which is occasionally written as \rm cm^2.

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