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Zepler [3.9K]
3 years ago
10

The gas in the piston is at constant temperature. A student increases the pressure on the piston from 2 atm to 3 atm. The observ

ation will be summarized in a row of the incomplete table below.
1
Boyle's law
?
?
2
Charles’s law
?
?
3
Gay-Lussac’s law
?
Volume, moles of gas
4
Combined gas law
?
?


Which row of the table and which observation would the student fill?

row 1, volume decreases when temperature decreases
row 1, volume decreases when pressure increases
row 3, volume decreases when temperature decreases
row 3, volume decreases when pressure increases
Chemistry
2 answers:
Andreas93 [3]3 years ago
8 0

Answer: B

Explanation:

Alborosie3 years ago
7 0
<span>The answer is row 1, volume decreases when pressure increases. The given condition is a demonstration of Boyle's Law, which tells that the volume of a given amount of gas reserved at constant temperature is contrariwise proportional to the pressure. When the pressure is augmented by pushing the piston downwards, the gas will be compacted and its volume will decrease.</span>
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How many moles of CO gas are in 34.6 L?
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moles of CO gas : 1.545

<h3>Further explanation</h3>

Standard conditions for temperature and pressure are used as a reference in certain calculations or conditions

There are 2 conditions that are usually used as a reference : STP and RTP

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SeF6 1. Lewis Structure 2. Perspective drawing 3. Number of atoms bonded to central atom 4. Number of non-bonding electron pairs
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The answer is- SF_{6} is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.

Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.

Determine the molecular geometry of SF_{6}.

  • Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
  • According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
  • Now, calculate the total number of valence electrons in SF_{6}.

Valence\ electrons\ in\ SF_{6}= Valence\ electrons\ in\ S +\ 6(Valence\ electrons\ in\ F)

Valence electrons of S = 6

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Thus, the valence electrons in SF_{6} are-

Valence\ number\ of\ electrons\ in\ SF_{6} = (6) + 6(7) = 48\ electrons.

  • The Lewis structure of SF_{6} is - (Image attached).
  • In the structure, the number of atoms bonded to central atom (S) = 6.
  • Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
  • Electronic geometry in case of 6 bond pairs is octahedral.
  • Molecular geometry us also octahedral with bond angles 90°.
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  • SF_{6} is a non-polar molecule.

To learn more about Lewis structures visit:

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