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4 years ago

Which property does a metal with a large number of free-flowing electrons most likely have?

Chemistry

2 answers:

Akimi4 [234]4 years ago

6 0

a metal with a large number of free-flowing electrons most likely have good conductivity

astra-53 [7]4 years ago

3 0

Answer: Option (d) is the correct answer.

Explanation:

Ability of an element or substance to conduct electricity is known as conductivity. Also, flow of electric current is the flow of free electrons.

It is known that metals contain more number of free electrons and they are good conductors of heat and electricity. Metals are hard substances.

Whereas non-metals are brittle and they are poor conductors of heat and electricity.

Thus, we can conclude that the property of a metal with a large number of free-flowing electrons most likely have good conductivity.

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netineya [11]

Vacuoles are storage bubbles found in cells. They are found in both animal and plant cells but are much larger in plant cells. Vacuoles might store food or any variety of nutrients a cell might need to survive. They can even store waste products so the rest of the cell is protected from contamination.

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4 years ago

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Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. The o

liberstina [14]

Answer: Molar concentration of the tree sap have to be 0.783 M

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iCRT$

where,

$\pi$ = osmotic pressure of the solution = 19.6 atm

i = Van't hoff factor = 1 (for non-electrolytes)

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = temperature of the solution = $32^oC=[273+32]=305K$

Putting values in above equation, we get:

$19.6atm=1\times C\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 305K$

$C=0.783M$

Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C

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3 years ago

When a sulfur atom gains its valence electrons to have 8, the charge on the resulting ion is

nikklg [1K]

When a sulfur atom gains its valence electrons to have 8, the charge on the resulting ion is stable since sulfur atom achieved the octet rule. An octet rule is the filling of 8 electrons in an atom.

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4 years ago

A circular flow of warmer fluid in cooler fluid is called a ( n)

7nadin3 [17]

This is called a convection current

7 0

4 years ago

Consider the balanced equation for the following reaction:

Zanzabum

Answer: The amount of carbon dioxide formed in the reaction is 5.663 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of oxygen gas = 8 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{8g}{32g/mol}=0.25mol$

For the given chemical equation:

$7O_2(g)+2C_2H_6(g)\rightarrow 4CO_2(g)+6H_2O(l)$

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 4 moles of carbon dioxide

So, 0.25 moles of oxygen gas will produce = $\frac{4}{7}\times 0.25=0.143mol$ of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.143 moles

Putting values in equation 1, we get:

$0.143mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(0.143mol\times 44g/mol)=6.292g$

To calculate the experimental yield of carbon dioxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Percentage yield of carbon dioxide = 90 %

Theoretical yield of carbon dioxide = 6.292 g

Putting values in above equation, we get:

$90=\frac{\text{Experimental yield of carbon dioxide}}{6.292g}\times 100\\\\\text{Experimental yield of carbon dioxide}=\frac{90\times 6.292}{100}=5.663g$

Hence, the amount of carbon dioxide formed in the reaction is 5.663 grams

7 0

3 years ago