What is the first anmial

Which element has the electron configuration [Rn] 7s2 5f14 6d4 ?

nexus9112 [7]

Answer:

Rn] 5f14 6d4 7s2 mp: none d: none. Seaborgium ..... Element. Density. Boiling or Melting Point in °C. Electron Configuration. Symbol.

Explanation:

3 0

3 years ago

Read 2 more answers

What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2?

Law Incorporation [45]

The answer is 0.975 L

Volume = mol/Molarity

We have molarity (0.788 M) and we need mol and volume. Let's first calculate number of moles of CaCl2 in 85.3 g:

Molar mass of CaCl2 is sum of atomic masses of Ca and Cl:
Mr(CaCl2) = Ar(Ca) + 2Ar(Cl) = 40 + 2 * 35.45 = 40 + 70.9 = 110.9 g/mol

So, if 110.9 g are in 1 mol, 85.3 g will be in x mol:
110.9 g : 1 mole = 85.3 g : x
x = 85.3 g * 1 mole / 110.9
x = 0.769 moles

Now, calculate the volume:
V = 0.769/0.788
V = 0.975 L

5 0

3 years ago

Which of the following statements about water is true?

Nikolay [14]

The correct option is: It's solid form is less dense than the liquid form.

7 0

3 years ago

Question 1 (True/False Worth 2 points) (04.03 LC) When Pb and AlCl3 react together, lead (Pb) can replace aluminum (Al) in the c

aivan3 [116]

Answer:

For 1: The correct answer is false.

For 2: The correct answer is $Na_3PO_4+3KOH\rightarrow 3NaOH + K_3PO_4$ , because K retains the same charge throughout the reaction.

For 3: The correct answer is $Zn+H_2SO_4\rightarrow ZnSO_4 + H_2$

For 4: The correct answer is a single replacement reaction takes place because sodium is more reactive than hydrogen.

For 5: The correct answer is False.

For 6: The correct answer is it is a single replacement reaction, and the cations in the two ionic compounds are different.

Explanation:

For 1:

This type or reaction is based on the reactivity series. If the metal which lies above in the series will replace the metal which lies below in the series easily.

From the reactivity table attached below, we know that lead lies below in the series to Aluminium and hence, it will not replace in the reaction.

$Pb+AlCl_3\rightarrow \text{No reaction}$

Hence, the correct answer is False.

For 2:

A balanced equation is defined as the equation in which there are same number of atoms present on the reactant side and the product side.

The balanced equation always follow Law of Conservation of Mass.

So, from the given options, the below equation is the balanced equation because K retains the same charge throughout the reaction.

$Na_3PO_4+3KOH\rightarrow 3NaOH + K_3PO_4$

For 3:

A single displacement reaction is a type of chemical reaction in which one element replaces another element in a chemical reaction. The element which is more reactive will replace the less less reactive element.

This is explained by reactivity series as the metal which lies above in the series will replace the metal which lies below in the series easily. From the given equations, the equation which is a type of single displacement reaction is:

$Zn+H_2SO_4\rightarrow ZnSO_4 + H_2$

$Ba(OH)_2+H_2SO_4\rightarrow BaSO_4 + 2H_2O$ : This equation is a type of double displacement reaction.

$2Mg+O_2\rightarrow 2MgO$ : This equation is a type of combination reaction.

$H_2O+CO_2\rightarrow H_2CO_3$ : This equation is a type of combination reaction.

For 4:

A single displacement reaction is a type of chemical reaction in which one element replaces another element in a chemical reaction.

$A+BC\rightarrow AC+B$

A double displacement reaction is a type of chemical reaction in which exchange of ins takes place.

$AB+CD\rightarrow AD+BC$

In the question, it is asked that sodium metal is reacting with water to produce hydrogen gas and sodium hydroxide. This reaction is a type of single displacement reaction because sodium is more reactive than hydrogen as shown in the reactivity series.

$2Na+2H_2O\rightarrow H_2+2NaOH$

For 5:

A single displacement reaction is a type of chemical reaction in which one element replaces another element in a chemical reaction. This reaction will not follow when an element replaces similar element.

Hence, the statement is False.