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olya-2409 [2.1K]
3 years ago
11

Solve for a 5/a - 2/1-a = 2/a-1 a=0 a=-1 a=1 none

Mathematics
1 answer:
podryga [215]3 years ago
8 0
Hello : 
\frac{5}{a} - \frac{2}{1-a} = \frac{2}{a-1} = \frac{5}{a}+ \frac{2}{a-1} = \frac{2}{a-1}
= \frac{5(a-1)+2a}{a(a-1)} = \frac{2a}{a(a-1)} 
(a \neq 1  ,  a \neq 0)

5a-5 +2a =2a
5a =5
a=1 ( refused)
conclusion : <span>none</span>
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What value of B makes the expression. x² + Bx + 81 a perfect square trinomial?
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Step-by-step explanation:

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Please help, and thank you!
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3. C

4. D

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3.

x^2+25=0\\x^2=-25\\x=\pm\sqrt{-25}

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4.

A quadratic equation has no real roots when the discriminant (\Delta) is negative. \Delta.

Let's try all the equations:

(A)

2x^2-7x-9=0\\\\\Delta=\sqrt{\left(-7\right)^2-4\cdot \:2\left(-9\right)}\\\Delta=\sqrt{\left(-7\right)^2+4\cdot \:2\cdot \:9}\\\Delta=\sqrt{121} \\\Delta=11

(B)

2x^2=7x\\2x^2-7x=0\\x(2x-7)=0\\x=0\\\text{or}\\2x-7=0\\2x=7\\\\

$x=\frac{7}{2} $

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2x^2+7x-9=0\\\Delta = \sqrt{7^2-4\cdot \:2\left(-9\right)}\\\Delta = \sqrt{7^2+4\cdot \:2\cdot \:9}\\\Delta = \sqrt{121} \\\Delta= 11

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