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olya-2409 [2.1K]
3 years ago
11

Solve for a 5/a - 2/1-a = 2/a-1 a=0 a=-1 a=1 none

Mathematics
1 answer:
podryga [215]3 years ago
8 0
Hello : 
\frac{5}{a} - \frac{2}{1-a} = \frac{2}{a-1} = \frac{5}{a}+ \frac{2}{a-1} = \frac{2}{a-1}
= \frac{5(a-1)+2a}{a(a-1)} = \frac{2a}{a(a-1)} 
(a \neq 1  ,  a \neq 0)

5a-5 +2a =2a
5a =5
a=1 ( refused)
conclusion : <span>none</span>
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Answer:

237

Step-by-step explanation:

This is a system of equations.

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Let's line them up

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Since we need to solve for the number of adult tickets, we want to get rid of the c variable. I'm going to multiply the entire first equation by -4 to do this. The second equation stays the same. Now, I have:

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