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3 years ago

What’s 38,000 * 16 please help me

Mathematics

2 answers:

Aliun [14]3 years ago

6 0

The answer for that is 608,000

Julli [10]3 years ago

3 0

Answer:

608,000

Step-by-step explanation:

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The difference between a number divided by 3 and 4 is 20

Rzqust [24]

Set the number to x.

$\frac{x}{3}-\frac{x}{4}=20$
$\frac{4x}{12}-\frac{3x}{12}=20$
$\frac{x}{12}=20$
$x=240$

Thus, the number is 240.

8 0

3 years ago

In how many ways can you place 50 identical balls in six distinct urns such that each urn contains an odd number of balls

mezya [45]

Answer:

80730

Step-by-step explanation:

The answer is c(27,5)=27*26*25*24*23/5!. Here is why.

Let us solve a simpler problem. In how many ways 25 identical balls can be placed in six distinct urns such that no urn is empty?

25 balls in a row make 24 places for five dividers, so the answer is c(24,5).

2. Next problem. In how many ways 50 identical balls can be placed in six distinct urns such that no urn is empty and each urn contains even number of balls.

We group 50 balls in 25 pairs, so the answer is the same as in the previous problem which is

c(48/2,5)=c(24,5).

Let us denote the content of each urn as

u(1),u(2),…u(6). Note that each u(i) is even. Denote u(i) as u(i)=2k(i) where k is a natural number. We have

2k(1)+2k(2)+2k(3)+2k(4)+2k(5)+2k(6)=50.

3. Now let us proceed to the original problem where odd number of balls in each urn is required.

We have

2k(1)-1+2k(2)-1+2k(3)-1+2k(4)-1+2k(5)-1+2k(6)-1=50 or

2k(1)+2k(2)+2k(3)+2k(4)+2k(5)+2k(6)=56.

So the original problem reduces to previous problem where even number of balls in each urn is required but the total number of balls is 56 instead of 50.

Its answer is c(54/2,5)=c(27,5).

8 0

3 years ago

Define maximum and minimum

NikAS [45]

Answer:

Maximum is the most allowed or the most your able to put on whatever requires Maximum of anything. Minimum is the Least allowed or the least your able to pu on whatever that requires minimum of anything

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Multiply each equation by a constant that would help to eliminate the y terms.

Zinaida [17]

Answer:

Therefore the required resulting equation is

$6x-15y=-63\\-15x+15y=90$