sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
<u>Step-by-step explanation:</u>
We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)
Given sequence is an AP with following parameters as :

So , Let's calculate how many terms are there as :
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Sum of an AP is :
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Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
Answer:
B. yes.
Step-by-step explanation:
dd_rrdrdy]uuhhhgffdddddddddddddddddddddd
Answer:
x = -12
y = 11
Step-by-step explanation:
i used substitution and let 'x' = 10 - 2y
3(10 - 2y) + 4y = 8
30 - 6y + 4y = 8
30 -2y = 8
-2y = -22
y = 11
x + 2(11) = 10
x + 22 = 10
x = -12